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o-na [289]
3 years ago
12

While performing the Acid-catalyzed Hydrolysis of Epoxides experiment you used a solution containing 1.84 mL of cyclohexene oxid

e. After the reaction was completed and worked up, you obtained 0.739 g of 1,2-cyclohexane diol. Calculate the moles of starting material used.
Chemistry
1 answer:
Elenna [48]3 years ago
3 0

Answer:

The moles of starting material is 1.8212 \times 10^{-2} mole

Explanation:

Given:

Cyclohexene oxide material is used

Density = 0.97\frac{g}{mL}

Volume = 1.84  mL

Formula of Cyclohexene oxide = C_{6} H_{10} O

Molar mass is given by,

C = 6 \times 12 = 72

H = 10 \times 1 = 10

O = 1 \times 16 = 16

⇒ m' = 96\frac{g}{mol}

Mass m = 0.97 \times 1.84 = 1.7848 g

Moles is given by,

  n = \frac{m}{m'}

  n = \frac{1.7848}{98}

  n = 1.8212 \times 10^{-2} mol

Therefore, the moles of starting material is 1.8212 \times 10^{-2} mole

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Calculate the concentration of acetate ion in a buffer solution made from 2.00 mL of 0.50 M acetic acid and 8.00 mL of 0.50 sodi
Lelu [443]

Answer:

1 M

Explanation:

Equation of reaction is;

CH3COOH + CH3COONa -------------------> 2CH3COO^- + NaH

1 moles of each of the reactants react to give 2 moles of the acetate ion.

From the question, we have that 2.00 mL that is (2÷1000)L of 0.50 M acetic acid reacted with 8.00 mL that is (8/1000)L of 0.50 sodium acetate.

Then from equation, n = CV -------------------------------------------(1).

Where n= number of moles, V= volume, C= concentration.

Number of moles,n of acetic acid = 0.50M× 2/1000L.

n(acetic acid)= 0.001 moles.

Number of moles,n of sodium acetate= 0.50M ×(8/1000)L.

n(sodium acetate)= 0.004 moles.

0.001 moles of acetic acid react with 0.004 moles of Sodium acetate

Therefore, acetic acid is the limiting reagent.

One mole of acetic acid produces 2 moles of acetate ion.

0.001 mole of acetic acid produces= 0.002 moles of acetate ion.

Using the equation (1) that is, n= CV.

0.002= C× 2/1000

C= 0.002/0.002

C= 1 M

8 0
3 years ago
Think about agriculture research which of the following statements is accurate?
irina [24]

A.genetic modification of food helps it grow more easily in certain areas

Explanation:

The statement genetic modification of food helps it grow more easily in certain areas is a form of agricultural research that is very accurate.

Genetically modifying food is common practice in order to encourage desirable and sustainable traits in plant species.

  • Drought resistant breeds can tolerate a much lower level of water in some specific areas.
  • Disease resistant breeds are more adapted to outbreaks of plant epidemics.
  • Overall, genetic modification of food helps them to grow and produce better.

learn more:

Genetic recombination brainly.com/question/12685192

#learnwithBrainly

4 0
4 years ago
PLEASE HELP WITH EASY 8th GRADE SCIENCE!!
atroni [7]
I think c is the right answer
8 0
3 years ago
Read 2 more answers
Answer the ones please get right
Natali [406]

Answer:

Hope this helps!

Explanation:

I would help you, but I won't. Because you take others people points without helping them and but random words. So, since you are doing that I won't be helping you <3. Thanks for the points idiot.

6 0
3 years ago
Green light has a wavelength of 550nm. What is the frequency of a photon of green light?
Vikki [24]

Answer:- Frequency is 5.4*10^1^4Hz .

Solution:- frequency and wavelength are inversely proportional to each other and the equation used is:

\nu =\frac{c}{\lambda }

where, \nu is frequency, c is speed of light and \lambda is the wavelength.

Speed of light is 3.0*10^8m/s .

We need to convert the wavelength from nm to m.

( 1nm=10^-^9m )

550nm(\frac{10^-^9m}{1nm})

= 5.5*10^-^7m

Now, let's plug in the values in the equation to calculate the frequency:

\nu =\frac{3.0*10^8m.s^-^1}{5.5*10^-^7m}

= 5.4*10^1^4s^-^1 or 5.4*10^1^4Hz

since, 1s^-^1=1Hz

So, the frequency of the green light photon is 5.4*10^1^4Hz .

4 0
3 years ago
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