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Bad White [126]
3 years ago
12

1. A piston having a diameter of 5.48 inches and a length of 9.50 in slides downward with a velocity, V, through a vertical pipe

. The downward motion is resisted by an oil film between the piston and the pipe wall. The film thickness is 0.002 inches and the cylinder weighs 0.5 lb. Compute the velocity, V if the oil viscosity is 0.016 lb*s/ft
2. Assume the velocity distribution in the gap is linear. (answer: 0.0046 ft/sec) I need to understand this for my quiz so please work steps clearly. Will Rate!!!"
Engineering
1 answer:
const2013 [10]3 years ago
3 0

Answer:

V = 0.00459 ft/s  

Explanation:

Since the Piston is moving downwards with a constant velocity V, from the first Newton’s law we know that all vertical forces, must have zero resultant (their sum over vertical axis must equal to zero). Therefore, force that pulls the piston down, is equalized by force of viscous friction Fd= Fvf = 0.5lb (lb here is the pound-force unit). We will relate F ѵ f  with τ and from that derive the equation for V.

Fѵf = τ  . A

Where τ  = µ. du/dy = µ . V/b  , and A = π . D . l from this Follows:

Fѵf= (V.  A .µ )/b     V= ( Fѵf .b )/(A.µ)    

Placing all the known values in the equation ( remember  to transform inches to feet, by multiplying inches values with the factor 1/12), we obtain :  

ft2

V = ((0.5lb)   .   (0.002/12 ft))/(π   .   (5.48/12 ft)  .  (9.50/12 ft)  .  (0.016 lb.s/(ft^2 )))

V = 0.00459 ft/s  

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An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500
max2010maxim [7]

Answer: The exit temperature of the gas in deg C is 32^{o}C.

Explanation:

The given data is as follows.

C_{p} = 1000 J/kg K,   R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)

P_{1} = 100 kPa,     V_{1} = 15 m^{3}/s

T_{1} = 27^{o}C = (27 + 273) K = 300 K

We know that for an ideal gas the mass flow rate will be calculated as follows.

     P_{1}V_{1} = mRT_{1}

or,         m = \frac{P_{1}V_{1}}{RT_{1}}

                = \frac{100 \times 15}{0.5 \times 300}

                = 10 kg/s

Now, according to the steady flow energy equation:

mh_{1} + Q = mh_{2} + W

h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}

C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}

(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}

(T_{2} - T_{1}) = 5 K

T_{2} = 5 K + 300 K

T_{2} = 305 K

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Therefore, we can conclude that the exit temperature of the gas in deg C is 32^{o}C.

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3 years ago
Which of the following headlines about the French Revolution is not true?
Sever21 [200]

Answer:

d) "Napoleon Declares Himself Holy Roman Emperor"

Explanation:

The French Revolution is defined as a period of the major social upheaval which began in the year 1787 and lasted till year 1799. This revolution completely redefined the the very nature of the political power in France. and also the relationship between the rulers of France and the people they governed.

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During the French revolution was at peak, the National Assembly issued the Declaration of the rights of the man to the public.

Maximilien Robespierre was considered to be one of the most influential figure and most important statesman during the French Revolution.

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3 years ago
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Answer:

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Explanation:

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