Answer:
The solution for the given problem is done below.
Explanation:
M1 = 2.0
= 0.3636
= 0.5289
= 0.7934
Isentropic Flow Chart: M1 = 2.0 ,
= 1.8
T1 =
(1.8)(288K) = 653.4 K.
In order to choke the flow at the exit (M2=1), the above T0* must be stagnation temperature at the exit.
At the inlet,
T02=
= (1.8)(288K) = 518.4 K.
Q= Cp(T02-T01) =
= 135.7*
J/Kg.
Answer:
,
,
, The cycle is irreversible.
Explanation:
The real cycle efficiency is:


The theoretical cycle efficiency is:


The reversible and real versions of the power cycle are described by the Clausius Inequalty:
Reversible Unit
Real Unit


The cycle is irreversible.
Answer:
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