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3 years ago

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Locate the centroid y¯ of the composite area. Express your answer to three significant figures and include the appropriate units

. y¯ = nothing nothing Request Answer Part B Determine the moment of intertia of this area about the centroidal x′ axis. Express your answer to three significant figures and include the appropriate units. Ix′ = nothing nothing Request Answer Provide Feedback

1 answer:

german3 years ago

4 0

Answer:

Please see the attached Picture for the complete answer.

Explanation:

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A guitarist would use a tuner to change which element of music?

Deffense [45]

Answer: The pitch

Explanation:

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3 years ago

Read 2 more answers

How many trips would one rubber-tired Herrywampus have to make to backfill a space with a geometrical volume of 5400 cubic yard?

nikklg [1K]

Answer:

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

Explanation:

a) By volume.

The shrinkage factor is:

$\frac{5400cu-yd}{1-0.25} =7200cu-yd$

The volume at loose is:

$V_{loose} =V_{bank} (1+swell-factor)=7200(1+0.2)=8640cu-yd$

If the Herrywampus has a capacity of 30 cubic yard:

$\frac{8640cu-yd}{30cu-yd/trip} =288trip$

b) By weight

The swell factor in terms of percent swell is equal to:

$pounds-per-cubic-yard-loose=\frac{pounds-per-cubic-yard-bank}{\frac{percent-swell}{100}+1 }$

$pounds-per-cubic-yard-loose=\frac{3000}{\frac{20}{100} +1} =2500lb/cu-yd$

The weight of backfill is:

$8640cu-yd*2500\frac{lb}{cu-yd} *\frac{1ton}{2000lb} =10800ton$

The Herrywampus has a capacity of 40 ton:

$\frac{10800}{40ton/trip} =270trip$

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

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3 years ago

Which of these is a characteristic of a reform movement?

Reika [66]

Answer:

distinguished from more radical social such as revolutionary

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3 years ago

This assignment will give you more experience on the use of loops In this project, we are going to compute the number of times a

musickatia [10]

Answer:

import java.io.BufferedReader;

import java.io.File;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

import java.util.StringTokenizer;

public class Tester {

public static void main(String[] args) throws IOException {

Scanner in=new Scanner(System.in);

System.out.println("Enter a Number =======>");

long N ;

while (!in.hasNextLong()) {

System.out.println("That's not a number!");

in.next();

}

N=in.nextLong();

System.out.println("Number Entered is =======>"+N);

System.out.println("Enter a Digit =======>");

int D;

while (!in.hasNextLong()) {

System.out.println("That's not a number!");

in.next();

}

D=in.nextInt();

System.out.println("Digit Entered is =======> "+ D);

long que=N;

int rem;

int count=0;

while(true){

long temp;

temp = (long)que/10;

rem = (int) (que % 10);

System.out.println(temp+" "+ que+" "+rem);

if(rem==D) count++;

que=temp;

if(que==0) break;

}

System.out.println("The number of "+ D+"'s in "+ N + " is "+ count );;

}

}

Explanation:

Divide the que variable by 10 and assign its result to the temp variable.
Calculate the remainder.
Increment the count if the remainder is equal to the value of D variable and assign the value of que to temp variable.

3 0

3 years ago

A dryer is shaped like a long semi-cylindrical duct of diameter 1.5 m. The base of the dryer is occupied with water-soaked mater

Anestetic [448]

Answer:

0.0371 kg/s.m

Explanation:

From the given information, let's have an imaginative view of the semi-cylinder; (The image is shown below)

Assuming the base surface of both ends of the cylinder is denoted by:

$A_1 \ and \ A_2$

Thus, using the summation rule, the view factor $F_{11$ and $F_{12$ is as follows:

$F_{11}+F_{12}=1$

Let assume the surface (1) is flat, the $F_{11} = 0$

Now:

$0+F_{12}=1$

$F_{12}=1$

However, using the reciprocity rule to determine the view factor from the dome-shaped cylinder $A_2$ to the flat base surface $A_1$ ; we have:

$A_2F_{21} = A_{1}F_{12} \\ \\ F_{21} = \dfrac{A_1}{A_2}F_{12}$

Suppose, we replace DL for $A_1$ and

$A_2$ = $\dfrac{\pi D}{2}$

Then:

$F_{21} = \dfrac{DL}{(\dfrac{\pi D}{2}) L} \times 1 \\ \\ =\dfrac{2}{\pi} \\ \\ =0.64$

Now, we need to employ the use of energy balance formula to the dryer.

i.e.

$Q_{21} = Q_{evaporation}$

But, before that; let's find the radian heat exchange occurring among the dome and the flat base surface:

$Q_{21}= F_{21} A_2 \sigma (T_2^4-T_1^4) \\ \\ Q_{21} = F_{21} \times \dfrac{\pi D}{2} \sigma (T_2^4 -T_1^4)$

where;

$\sigma = Stefan \ Boltzmann's \ constant$

$T_1 = base \ temperature$

$T_2 = temperature \ of \ the \ dome$

∴

$Q_{21} = 0.64 \times (\dfrac{\pi}{2}\times 1.5) \times 5.67 \times 10^4 \times (1000^4 -370^4)\\ \\ Q_{21} = 83899.15 \ W/m$

Recall the energy balance formula;

$Q_{21} = Q_{evaporation}$

where;

$Q_{evaporation} = mh_{fg}$

here;

$h_{fg}$ = enthalpy of vaporization

m = the water mass flow rate

∴

$83899.15 = m \times 2257 \times 10^3 \\ \\ m = \dfrac{83899.15}{ 2257 \times 10^3 }\\ \\ \mathbf{m = 0.0371 \ kg/s.m}$

6 0

2 years ago