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3 years ago

What are isotopes..??

Chemistry

1 answer:

tatuchka [14]3 years ago

6 0

Answer:

each of two or more forms of the same element that contain equal numbers of protons but different number of nurtrons

in there nucleir

Explanation:

.....

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Vinil7 [7]

12: They have more moons because they are bigger. They have a greater gravity field so they pull more on other objects. Gravity is like a blanket held taunt. If you put a big bowling ball in the center and place an orange on the outside the orange is going to want to go to the center, where the bowling ball is. Now if you add angular momentum to the equation you get gravity. Of course it isn't that simple but its the jist of it. Therefore, since Saturn and Jupiter have a higher gravitational pull on other celestial objects they pull on more matter around them, like asteroids and such. These asteroids clump together and form their planets.

7 0

3 years ago

Read 2 more answers

In the reaction A + B + C >> D, what are the products?

Kisachek [45]

Answer:

D only

Explanation:

The products are the stuff on the right of the yield sign so the answer is D only.

3 0

3 years ago

List three properties you would expect the metal zinc to have

Natali5045456 [20]

Low melting point
Low boiling point
Electric conductor

7 0

4 years ago

Read 2 more answers

Initially, [NH3(g)] = [O2(g)] = 3.60 M; at equilibrium [N2O4(g)] = 0.60 M. Calculate the equilibrium concentration for NH3.

natima [27]

The question is incomplete, here is the complete question:

Consider the reaction $4NH_3(g)+7O_2(g)\rightarrow 2N_2O_4(g)+6H_2O(g)$

Initially, $[NH_3(g)]=[O_2(g)]$ = 3.60 M; at equilibrium $[N_2O_4(g)]=0.60M$ . Calculate the equilibrium concentration for $NH_3$

<u>Answer:</u> The equilibrium concentration of ammonia is 2.8 M

<u>Explanation:</u>

We are given:

Initial concentration of $[NH_3(g)]$ = 3.60 M

Initial concentration of $[O_2(g)]$ = 3.60 M

For the given chemical equation:

$4NH_3(g)+7O_2(g)\rightarrow 2N_2O_4(g)+6H_2O(g)$

Initial: 3.60 3.60

At eqllm: 3.60-4x 3.60-7x 2x 6x

We are given:

Equilibrium concentration of $[N_2O_4(g)]$ = 0.60 M

Evaluating the value of 'x'

$\Rightarrow 2x=0.60\\\\\Rightarrow x=\frac{0.60}{2}=0.2$

So, equilibrium concentration of $NH_3=(3.60-4x)=(3.60-(4\times 0.2))=2.8M$

Hence, the equilibrium concentration of ammonia is 2.8 M

6 0

3 years ago

A 4.305-g sample of a nonelectrolyte is dissolved in 105 g of water. the solution freezes at -1.23c. calculate the molar mass of

amid [387]

The answer is 62.00 g/mol.
Solution:
Knowing that the freezing point of water is 0°C, temperature change Δt is
Δt = 0C - (-1.23°C) = 1.23°C
Since the van 't Hoff factor i is essentially 1 for non-electrolytes dissolved in water, we calculate for the number of moles x of the compound dissolved from the equation
Δt = i Kf m
1.23°C = (1) (1.86°C kg mol-1) (x / 0.105 kg)
x = 0.069435 mol
Therefore, the molar mass of the solute is
molar mass = 4.305g / 0.069435mol = 62.00 g/mol

6 0

3 years ago

What are isotopes..??​

What are isotopes..??