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EastWind [94]
3 years ago
6

A real image is four times as far from a lens as is theobject.

Physics
1 answer:
saveliy_v [14]3 years ago
3 0

Answer:

1.25 focal lengths

Explanation:

The lens equation states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the object distance

q is the image distance

In this problem, the image is 4 times as far from the lens as is the object: this means that

q=4p

If we substitute this into the lens equation and we rearrange it, we get

\frac{1}{f}=\frac{1}{p}+\frac{1}{4p}=\frac{4+1}{4p}=\frac{5}{4p}\\p=\frac{5}{4}f=1.25 f

so, the object distance measured in focal lengths is

1.25 focal lenghts

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Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a curre
Igoryamba

Answer:

a)\frac{F_1}{L}=1.95*10^-^5N

b)\frac{F_2}{L}=1.95*10^-^5N

Explanation:

From the question we are told that:

Distance between wires d=32.2

Wire 1 current I_1=2.75

Wire 2 current I_2=4.33

a)

Generally the equation for Force on l_1 due to I_2 is mathematically given by

F_1=I_1B_2L

Where

B_2=Magnetic field current by I_2

B_2=\frac{\mu *i_2}{2\pi d}

Therefore

F_1=I_1B_2L

F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L

\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }

\frac{F_1}{L}=1.95*10^-^5N

b)

Generally the equation for Force on I_2 due to I_1 is mathematically given by

F_2=I_2B_1L

Where

B_1=Magnetic field current by I_2

B_1=\frac{\mu *I_1}{2\pi d}

Therefore

\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})

\frac{F_2}{L}=1.95*10^-^5N

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3 years ago
Gravitational force between two objects increases as mass increases and distance
Tems11 [23]
Distance decreases.
6 0
3 years ago
can you suggest improvement that can be made towards the design of siphon so that the transfer of liquid is much higher.​
ahrayia [7]

Answer:

A siphon is a tube that makes use of the potential energy of fluid at an elevated level to transfer the fluid to a lower level, due to pressure differences between the inlet and the outlet points of the tube, such that the pressure at the outlet is higher than the pressure at the inlet

The pressure energy is converted into velocity (kinetic) energy, and therefore, in other to increase the flow rate through the tube of a siphon, with constant diameter, the level of the fluid in the container at the inlet (supply) of the siphon is raised higher than the level at the outlet receiving) container or the outlet point of the siphon tube

The larger the difference between the inlet and outlet levels, the faster the transfer of fluid by the siphon

Explanation:

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3 years ago
You are given aqueous solutions of six different substances and asked to determine whether they are strong, weak, or nonelectrol
kogti [31]

Answer:

Answer is explained below;

Explanation:

Electrolytes are any substances that dissociate into charged particles called ions when dissolved in water. The positively charged ions called cations and the negatively charged ions called anions move toward the negative and positive terminals (cathode and anode) of an electric circuit.

When a substance dissolved in water completely dissociates into ions, it is called a strong electrolyte. The aqueous solutions containing strong electrolytes conduct electricity very well and the examples include strong acids and soluble ionic compounds such as barium chloride, sodium hydroxide, etc.  

When a substance dissolved in water does not completely dissociate into ions, it is called a weak electrolyte. Since the aqueous solutions containing weak electrolytes have relatively few ions, their electrical conductivity is very low compared to the solutions containing strong electrolytes. Examples of weak electrolytes include weak acids and bases like acetic acid, ammonia, etc.

When a substance does not dissociate into ions when dissolved in water, it is called a nonelectrolyte. Since the aqueous solutions containing nonelectrolytes do not contain any ions, such solutions do not conduct electricity. Examples of nonelectrolytes are ethanol, aldehydes, glucose, ketones, etc.

If a solution contains dissolved ions, it conducts electricity and as the ion concentration increases, the conductivity also increases. To determine whether the aqueous solutions of six different substances are strong, weak, or nonelectrolytes, we can test them by applying a voltage to electrodes immersed in the solutions and a light bulb. By observing the brightness of the light bulb or by measuring the flow of electrical current, we can find out which solution contains a strong electrolyte or weak electrolyte, or nonelectrolyte.

If the solution contains a nonelectrolyte, the current flow is nil and the light bulb does not glow. If the solution contains a strong electrolyte, the current flow is very strong and so the brightness of the light bulb is very high. If the solution contains a weak electrolyte, the current flow is much low compared to the strong electrolyte and the light bulb glows, but the brightness is very low.

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3 years ago
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Zinaida [17]

Answer:

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2 years ago
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