Answer:
because energy will be lost due to friction, sound, and heat (arguably similar to friction) and ENERGY MUST STAY THE SAME so it is IMPOSSIBLE for the ball to bounce higher than when dropped!
Given:
v = 50.0 m/s, the launch velocity
θ = 36.9°, the launch angle above the horizontal
Assume g = 9.8 m/s² and ignore air resistance.
The vertical component of the launch velocity is
Vy = (50 m/s)*sin(50°) = 30.02 m/s
The time, t, to reach maximum height is given by
(30.02 m/s) - (9.8 m/s²)*(t s) = 0
t = 3.0634 s
The time fo flight is 2*t = 6.1268 s
The horizontal velocity is
u = (50 m/s)cos(36.9°) = 39.9842 m/s
The horizontal distance traveled at time t is given in the table below.
Answer:
t, s x, m
------ --------
0 0
1 39.98
2 79.79
3 112.68
4 159.58
5 199.47
6 239.37
Answer: The hypotenuse is 26 ft.
Step-by-step explanation: Let's call the shorter leg of the triangle x. The hypotenuse would be x + 16 and the other leg is y.
As the area is 120, we know that x.y/2 = 120 (because it's a right triangle).
This way, y = 240/x
we know that in a right triangle, we have a² = b² + c²
(x + 16)² = x² + y²
(x + 16)² = x² + (240/2)²
x² + 32x + 256 = x² + 57600/x²
32x + 256 = 57600/x²
32x³ + 256x² = 57600 (÷ 32)
x³ + 8x² = 1800
x = 10
∴
x + 16 = 26
y = 240/10 = 24
Answer:
a).p=15.67kg*m/s
b). F=7.83N
Explanation:
change in momentum is the subtraction from "after momentum" of the "before momentum" as momentum is a vector quantity this is a vector subtraction.
initial momentum of ball
m1v1 = (0.145)(44.0) = 6.38 kg-m/s
after momentum
m1v2 = (0.145)(64.0) = 9.28 kg-m/s
since these momentums are 180° opposite one must be called negative so their difference
6.38+9.28= 15.67 kg-m/s
change in momentum = 15.67 kg-m/s ANS a1
Impulse = change in momenutm = 15.67 ANS a2
b)
Impulse =Favg*t
I=(2.00)Favg
Impulse from (a2) = 15.67
Favg = 15.67/2.00 =
F= 7.83 N