<span>The period of a wave can be calculate according T = 1 / f
where T is wave period and f is frequency,
then in our problem we have a wave of 100 Hz so:
T = 1 / 100 = 0.01 seconds
The wave have a period of 0.01 seconds.
Optinaly we could also calculate the speed: V=wavelenght/period= 2/0.01= 200 m/s</span>
Answer:
21.6 kN
Explanation:
F = m * a
F = 54 000 * .4 = 21600 N
No. The forces of gravity between them would remain unchanged after those three changes.
Answer:
Explanation:
Reaction force of inclined surface
R = mgcos30
=60 x 9.8 x .866
= 509 N
Force of kinetic friction
= .12 x 509
= 61.08 N
b )
net force downwards = mgsinθ - μmgcosθ
acceleration = g sinθ - μgcosθ
9.8 sin30 - .12 x 9.8 x cos30
= 4.9 - 1.018
a= 3.88 m /s²
c )
v² = 2as
= 2 x 3.88 x 20
v = 12.46 m /s
Correct answer is 2.7 x 10^-3 J/m3
I hope that helps ! <33