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Nataly [62]
3 years ago
13

A car weighing 11.1 kN and traveling at 13.4 m/s without negative lift attempts to round an unbanked curve with a radius of 61.0

m. (a) What magnitude of the frictional force on the tires required to keep the car f static friction between the tire or not ("yes" or "no")? on its circular If the coefficient ro s 0.35, is the attempt at taking the curve successf (a) Number Units (b)
Physics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

Well..

Explanation:

That's impossible. I know because I once weighed 11.1 kN, and I was temporarily immobile. It's probably the same for a car, and therefore it can not be "traveling" anywhere at all.. unless you put the car on an airplane or a boat or something.

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A student is examining a bacterium under the microscope. The E. coli bacterial cell has a mass of m = 0.900 fg (where a femtogra
just olya [345]

Answer:

9.73 x 10⁻¹⁰ m

Explanation:

According to Heisenberg uncertainty principle

Uncertainty in position x uncertainty in momentum ≥ h / 4π

Δ X x Δp ≥ h / 4π

Δp = mΔV

ΔV = Uncertainty in velocity

= 2 x 10⁻⁶ x 3 / 100

= 6 x 10⁻⁸

mass m = 0.9 x 10⁻¹⁵ x 10⁻³ kg

m = 9 x 10⁻¹⁹

Δp = mΔV

= 9 x 10⁻¹⁹ x 6 x 10⁻⁸

= 54 x 10⁻²⁷

Δ X x Δp ≥ h / 4π

Δ X x  54 x 10⁻²⁷ ≥ h / 4π

Δ X = h / 4π x 1 /  54 x 10⁻²⁷

= \frac{6.6\times10^{-34}}{4\times3.14\times54\times10^{-27}}

= 9.73 x 10⁻¹⁰ m

7 0
3 years ago
PLEASE SOMEONE ANSWER!!! thank you so so so much!!!!
Oduvanchick [21]

Answer:

As much I know the gravity on moon is 1.62m/s२.

7 0
3 years ago
The overall energy involved in the formation of CsCl from Cs(s) and Cl2(g) is −443 kJ/mol. Given the following information: heat
german

Answer :  The magnitude of the lattice energy for CsCl is, 667 KJ/mole

Explanation :

The steps involved in the born-Haber cycle for the formation of CsCl :

(1) Conversion of solid calcium into gaseous cesium atoms.

Cs(s)\overset{\Delta H_s}\rightarrow Cs(g)

\Delta H_s = sublimation energy of calcium

(2) Conversion of gaseous cesium atoms into gaseous cesium ions.

Ca(g)\overset{\Delta H_I}\rightarrow Ca^{+1}(g)

\Delta H_I = ionization energy of calcium

(3) Conversion of molecular gaseous chlorine into gaseous chlorine atoms.

Cl_2(g)\overset{\frac{1}{2}\Delta H_D}\rightarrow Cl(g)

\Delta H_D = dissociation energy of chlorine

(4) Conversion of gaseous chlorine atoms into gaseous chlorine ions.

Cl(g)\overset{\Delta H_E}\rightarrow Cl^-(g)

\Delta H_E = electron affinity energy of chlorine

(5) Conversion of gaseous cations and gaseous anion into solid cesium chloride.

Cs^{1+}(g)+Cl^-(g)\overset{\Delta H_L}\rightarrow CsCl(s)

\Delta H_L = lattice energy of calcium chloride

To calculate the overall energy from the born-Haber cycle, the equation used will be:

\Delta H_f^o=\Delta H_s+\Delta H_I+\Delta H_D+\Delta H_E+\Delta H_L

Now put all the given values in this equation, we get:

-443KJ/mole=76KJ/mole+376KJ/mole+121KJ/mole+(-349KJ/mole)+\Delta H_L

\Delta H_L=-667KJ/mole

The negative sign indicates that for exothermic reaction, the lattice energy will be negative.

Therefore, the magnitude of the lattice energy for CsCl is, 667 KJ/mole

5 0
3 years ago
I need help asap plss this is important ​
Lady_Fox [76]
I think it would be “use reasoning statements to show how the data supports your claim”
4 0
3 years ago
Read 2 more answers
Take the following measured gauge (or gage) pressures and convert them to absolute pressures in both kPa and psi units for an am
mamaluj [8]

Answer:

Explanation:

Given

ambient Pressure =98.10 kPa

(a)gauge pressure 152 kPa

we know

Absolute pressure=gauge pressure+Vacuum  Pressure

P_{abs}=152+98.10=250.1 kPa or 36.27 psi

(b)P_{gauge}=67.5 Torr or 8.99 kpa

as 1 Torr is 0.133 kPa

P_{abs}=8.99+98.10=107.09 kPa or 15.53 psi

(c)P_{vaccum}=0.1 bar or 10 kPa

Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi

as 1 kPa is equal to 0.145 psi

(d)P_{vaccum}=0.84 atm  or 85.113 kPa

as 1 atm is equal to 101.325 kPa

P_{abs}=98.10-85.11=12.99 kPa or 1.88 psi

6 0
3 years ago
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