Answer:
13. ![\frac{\sqrt[5]{x^4} }{x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B5%5D%7Bx%5E4%7D%20%7D%7Bx%7D)
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14. 
15. 2.
Step-by-step explanation:
13. 
= 
= 
= 
= 
= 
= 
= .
14. 
.
15. ![\sqrt[3]{2} * \sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D%20%2A%20%5Csqrt%5B3%5D%7B4%7D)
= ![\sqrt[3]{2 * 4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%204%7D)
= ![\sqrt[3]{2 * 2 * 2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%202%20%2A%202%7D)
= ![\sqrt[3]{2 ^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%5E3%7D)
= 2.
Hope this helps!
Factor by grouping. Group up the terms into pairs, factor each pair, then factor out the overall GCF.
x^3 + 2x^2 - 16x - 32
(x^3 + 2x^2) + (-16x-32) ... pair up terms
x^2(x + 2) + (-16x - 32) ... factor x^2 from the first group
x^2(x + 2) - 16(x + 2) ... factor -16 from the second group
(x^2 - 16)(x + 2) .... factor out (x+2)
(x - 4)(x + 4)(x + 2) .... Use the difference of squares to factor x^2-16
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The original expression completely factors to (x - 4)(x + 4)(x + 2)
The three factors are x - 4 and x + 4 and x + 2
Step-by-step explanation:
2x + 5 (y-1)
16+20
=36
hope it helps you
