Metal things that pull together
Answer:
(a) (B)
Explanation:
We have given the the speed of the electron =10^6 m/sec
The time period of the electron is given by where r is the Bohr radius, which is equal to
So time period
(A) We know that current
(B) Magnetic moment is given by , where I is current and A is area
So
Answer:
E = 4.78*10^6 N/C
Explanation:
In this case you have to take into account that both magnetic force and electric force must be equal
However, you have to know first what is the speed of the electron by using the expression for the kinetic energy (1keV=1000*1.6*10^{-19}J):
by replacing in the expression for the forces you have
HOPE THIS HELPS!!
Answer:
Rounded to three significant figures:
(a) .
(b) .
Explanation:
Consider a double-slit experiment where a wide beam of monochromatic light arrives at a filter with a double slit. On the other side of the filter, the two slits will appear like two point light sources that are in phase with each other. For each point on the screen, "path" refers to the length of the segment joining that point and each of the two slits. "Path difference" will thus refer to the difference between these two lengths.
Let denote a natural number (.) In a double-split experiment of a monochromatic light:
- A maximum (a bright fringe) is produced when light from the two slits arrive while they were in-phase. That happens when the path difference is an integer multiple of wavelength. That is: .
- Similarly, a minimum (a dark fringe) is produced when light from the two slits arrive out of phase by exactly one-half of the cycle. For example, The first wave would be at peak while the second would be at a crest when they arrive at the screen. That happens when the path difference is an integer multiple of wavelength plus one-half of the wavelength: .
<h3 /><h3>Maxima</h3>
The path difference is at a minimum (zero) at the center of the screen between the two slits. That's the position of the first maximum- the central maximum, a bright fringe where in .
The path difference increases while moving on the screen away from the center. The first order maximum is at where .
Similarly, the second order maximum is at where . For the light in this question, at the second order maximum: .
- Central maximum: , such that .
- First maximum: , such that .
- Second maximum: , such that .
<h3>Minima</h3>
The dark fringe closest to the center of the screen is the first minimum. at that point.
Add one wavelength to that path difference gives another dark fringe- the second minimum. at that point.
- First minimum: , such that .
- Second minimum: , such that .
For the light in this question, at the second order minimum: .