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Vinvika [58]
3 years ago
8

If a cup of coffee is at 90°C and a person with a body temperature of 36'C touches it,how will heat flow between them

Physics
1 answer:
Arlecino [84]3 years ago
5 0

Answer:

the heat always transfers from high temperature to low temperature body without aid of any external energy to this law the heat transfers from cup of coffee to the person body until both bodies reaches to the equilibrium state    

Explanation:

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The algebraic expression for the component of the normal force in the vertical direction is Force= product of mass and area.

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1 year ago
A 100.0 mL sample of 1.020 M HCl is mixed with a 50.0 mL sample of 2.040 M NaOH in a Styrofoam cup. If both solutions were initi
I am Lyosha [343]

Answer:

t_2 = 33.793

Explanation:

Given data:

0.1 L HCl × 1.020 mol/L = 0.102 mol HCL

0.05 L NaOH × 2.040 mol/L = 0.102 mol NaOH

NaOH + HCl \rightarrow  H_2O + NaCl

0.102 mol HCl /1 mol HCl × 1 mol H2O = 0.102 mol H2O

0.102 mol H2O / 1 mol H2O × 57000 J = 5814 J

V(t ) = V_1+V_2 = 100 + 50 = 150 mL

M(t)=150*1=150 g

we know that heat energy is given as

Q = mc(t_2 - t_1)

where c is specific heat

total energy released is = 57 \times 0.102 = 5.814 kJ

5814 = 150 \times 4.184 \times (t_2 - 24.53)

t_2 = 33.793

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What type of pressure is transmitted by fluids
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4 years ago
When operated on a household 110.0 V line, typical hair dryers draw about 1650 W of power. The current can be modeled as a long,
Andre45 [30]

Explanation:

Given that,

Voltage of household line, V = 110 V

Power of the hairdryer, P = 1650 W

During use, the current is about 1.95 cm from the user's hand.

(a) Power is given by :

P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1650\ W}{110\ V}\\\\I=15\ A

(b) Again the power is given by :

P=\dfrac{V^2}{R}

R is resistance of the dryer

R=\dfrac{V^2}{P}\\\\R=\dfrac{(110)^2}{1650}\\\\R=7.34\ \Omega

(c) The magnetic field produced by the dryer at the user's hand is given by :

B=\dfrac{\mu_o I}{2\pi r}\\\\B=\dfrac{4\pi \times 10^{-7}\times 15}{2\pi \times 1.95\times 10^{-2}}\\\\B=1.53\times 10^{-4}\ T

Hence, this is the required solution.

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