Question

A coil of 1,000 turns encloses an area of 85 cm^2. It is rotated in 0.090 s from a position where its plane is perpendicular to Earth's magnetic field to one where its plane is parallel to the field. If the strength of the field is 6.0 x 10^-5 T, what is the average emf induced in the coil (in mV)?

Answer 1

Answer:

The average emf induced in the coil is $5.6\times10^{-3}\ mV$.

Explanation:

Given that,

Number of turns = 1000 turns

Area = 85 cm²

Time = 0.090 s

Its plane is perpendicular to Earth's magnetic field.

Angle = 0°

Magnetic strength $B=6.0\times10^{-5}\ T$

We need to calculate the magnetic flux

Using formula of magnetic flux

$\phi=BA\cos\theta$

Put the value into the formula

$\phi=6.0\times10^{-5}\times85\times10^{-4}\times\cos0^{\circ}$

$\phi =6.0\times10^{-5}\times85\times10^{-4}\times1$

$\phi=5.1\times10^{-7}\ Wb$

We need to calculate the average emf induced in the coil

$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{5.1\times10^{-7}}{0.090}$

$\epsilon=0.0000056\ N$

$\epsilon =5.6\times10^{-3}\ mV$

Hence, The average emf induced in the coil is $5.6\times10^{-3}\ mV$.