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xeze [42]
4 years ago
6

a child drops a ball from a window. The ball strikes the ground in 3.0seconds. What is the velocity if the ball the instant befo

re it hits the ground
Physics
2 answers:
fredd [130]4 years ago
6 0

Terminal velocity (Maximum velocity) is 9.8 meters a second. m/s.

If you wanted the exact answer, you would need the distance from the window to the ground; and than divide by 3.0. Otherwise, 9.8 meters a second would be your best bet.

Novosadov [1.4K]4 years ago
3 0

Answer:

v_f = 29.43 m/s

Explanation:

As we know that the ball is dropped from rest

So here we know acceleration of the object is due to gravity

So we will have

a = 9.81 m/s^2

now we have

v_f = v_i + at

here we have

v_i = 0

a = 9.81 m/s^2

t = 3.0 s

now from above equation we have

v_f = 0 + (9.81)(3)

v_f = 29.43 m/s

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When climbing a steep hill, would you want a larger or smaller bicycle gear?
DochEvi [55]

Answer:

Usually when climbing, it's best to be in the small front ring and the largest back ring. If your cadence is about 100 rpm, then whatever gear you're in is fine. It depends on the road, but as long as your pedaling is at a level you're comfortable with, you're fine.

Explanation:

Google answer by the way.

3 0
3 years ago
Before using a string in a comparison, you can use either the To Upper method or the To Lower method to convert the string to up
Burka [1]

Answer:

True

Explanation:

If there's no preference over the string case (upper case or lower case), one can convert both strings to upper case or to lowercase and then compare the converted strings to test if they're equal or not.

An Illustration is

string a = "Boy"

string b = 'bOy"

if(a.ToUpper() == b.ToUpper() || a.ToLower() == b.ToLower())

{

Print "Equal Strings"

}

else

{

Print "Strings are not equal";

}

The above will first convert both strings and then compare.

Since they are the same (after conversion), the statement "Equal Strings" will be printed, without the quotes

5 0
4 years ago
Which one of these is a chemical change?
satela [25.4K]
Burning a log because you are turning the log into ash from wood.
3 0
4 years ago
Read 2 more answers
A 5.0-V battery is places in series with two 1.25-Ω resistors. Determine the current through each resistor.
Nuetrik [128]

Answer:

Current through each resistor is 2 A.

Explanation:

Given that,

Voltage of a battery, V = 5 volts

Resistance 1, R = 1.25 ohms

Resistance 2,R' = 1.25 ohms

Both resistors are connected in series. The equivalent resistance is given by :

R" = R + R'

R" = 1.25 + 1.25

R" = 2.5 ohms

The current flowing throughout all resistors is same in series combination of resistors. Current can be calculated using Ohm's law as :

I=\dfrac{V}{R"}

I=\dfrac{5\ V}{2.5}

I = 2 A

So, the current through each resistor is 2 A. Hence, this is the required solution.

6 0
4 years ago
A 2.0-kg block is held at rest against a spring of constant 2700 N/m, compressing it 5.5 cm. The block and the spring are locate
KonstantinChe [14]

Answer:

a) 4.1 J

b) -14 J

c) 4.8 m/s

Explanation:

The energy stored in the spring is given by:

U_e=\frac{1}{2}*K*x^2\\\\U_e=\frac{1}{2}*2700N/m*(5.5*10^{-2}m)^2\\\\U_e=4.1J

The mechanical energy loss is because of the work done by the friction force.

The friction force (only presented on the inclined surface) is given by:

F_f=\µ*F_N

F_N=2.0kg*9.8m/s^2*cos(35)\\F_N=16N\\F_f=0.29*16N=4.6N

We need to calculate the length of the ramp in order to calculate the work, the length of the ramp is the hypotenuse:

sin(\theta)=\frac{OC}{h}\\h=\frac{OC}{sin(\theta)}\\\\h=\frac{1.7m}{sin(35)}\\\\h=3.0m

So the work done by the friction force is:

W_f=F_f*d*cos(\alpha)\\W_f=4.6N*3.0*cos(180)\\W_f=-14J

the angle is 180 degrees because the force is opposite to the motion.

In order the know the final velocity we need to apply the Energy Conservation Theorem:

K_1+U_{g1}+U_{e}+W_f=K_2+U_{g2}\\\\0+m*g*h_1+4.1J-14J=\frac{1}{2}*m*v^2+m*g*h_2\\\\2.0kg*9.8m/s^2*1.7m+4.1J-14J=\frac{1}{2}*2.0kg*v^2+2.0kg*9.8m/s^2*(0)\\\\33J+4.1J-14J=v^2\\\\v=\sqrt{23.1}\\\\v=4.8m/s

5 0
3 years ago
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