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valentina_108 [34]
2 years ago
5

Which law of motion explains what happens during a ride on the bumper cars ?

Physics
1 answer:
fomenos2 years ago
8 0

Answer:

Newtows first law of motion

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Do you think most people follow the recommended guidelines for an adequate exercise routine?
blondinia [14]

Personally, I know that I don't however it all depends on the person's lifestyle, health, and resoucres, such as if they are able to complete the excersise or have enough money fore equpemnt. To be safe, I would say that the majority of people do follow the guidelines although they may manipulate it to fit their best interest.

6 0
3 years ago
check the file.........................................................................................................
White raven [17]

What is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the  frequency of the oscillating body is 50Hz

<h3>What is frequency?</h3>

Frequency of an oscillating body can be defined as the number of complete oscillations per unit time

Frequency is measured in hertz (Hz).

Also, the frequency of 1Hz is one oscillation per second.

frequency = number of oscillations/ time taken

frequency = 500/10 = 50 Hz

Thus, what is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the  frequency of the oscillating body is 50Hz

Learn more about frequency here:

brainly.com/question/1199084

#SPJ1

6 0
2 years ago
In a football game, a 96 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vi
fredd [130]

Answer:

V = 0.074 m/s

Explanation:

given,

mass of the receiver, M = 96 Kg

mass of the ball, m = 0.42 Kg

initial speed of the ball, v = 17 m/s

initial speed of the receiver = 0 m/s

final speed.V = ?

using conservation of momentum

M u + m v = (M + m) V

0 + 0.42 x 17 = (96+0.42) V

96.42 V = 7.14

V = 0.074 m/s

hence, Speed after catching the ball is equal to 0.074 m/s

7 0
4 years ago
In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6
Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

         \lambda = \dfrac{h}{mv}

         1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}

         v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}

              v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

     E = \dfrac{1}{2}mv^2

     E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2

            E = 2.5 x 10⁻¹⁴ J

8 0
3 years ago
Both longitudinal and transverse waves transmit
Nastasia [14]
Sounds but not solids

hoped this helped  
5 0
4 years ago
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