Answer:
a) R(fw) = 46.75*10⁶ (N)
b) R(rwi) = 70.125*10⁶ [N]
Explanation: See Attached file (the rectangle stands for a jet)
The diagram shows forces acting on the jet
Let R(fw) Reaction of front wheels and
R(rw) Reaction of rear wheels
Now we apply the Stevin relation, for R(fw) and a jet weight as follows
R(fw)/ 4 = 187*10⁶ / 16
Then :
R(fw) = ( 1/4) *187*10⁶ ⇒ R(fw) = 46.75*10⁶ (N)
And e do the same for the reaction on rear wheels
R(rw) / 12 = 187*10⁶ /16 ⇒ R(rw) =(3/4)*187*10⁶
R(rw) = 140,25*10⁶ [N]
The last expression is for the whole reaction, and must be devide by 2
because that force is exerted for two wheels, therefore on each of the two rear wheels the reaction will be:
R(rwi) = 70.125*10⁶ [N]
Explanation:
The given data is as follows.
Electric field between plates without dielectric, ![E_{1} = 3.50 \times 10^{5} V/m](https://tex.z-dn.net/?f=E_%7B1%7D%20%3D%203.50%20%5Ctimes%2010%5E%7B5%7D%20V%2Fm)
Electric field between the plates with dielectric,
.
Permittivity of free space,
= ![8.85 \times 10^{-12} C^{2}/Nm^{2}](https://tex.z-dn.net/?f=8.85%20%5Ctimes%2010%5E%7B-12%7D%20C%5E%7B2%7D%2FNm%5E%7B2%7D)
Now, we will determine the charge density as follows.
![\sigma_{i} = \epsilon_{o}(E_{1} - E_{2})](https://tex.z-dn.net/?f=%5Csigma_%7Bi%7D%20%3D%20%5Cepsilon_%7Bo%7D%28E_%7B1%7D%20-%20E_%7B2%7D%29)
= ![8.85 \times 10^{-12} \times (3.50 \times 10^{5} - 2.40 \times 10^{5})](https://tex.z-dn.net/?f=8.85%20%5Ctimes%2010%5E%7B-12%7D%20%5Ctimes%20%283.50%20%5Ctimes%2010%5E%7B5%7D%20-%202.40%20%5Ctimes%2010%5E%7B5%7D%29)
= ![9.735 \times 10^{-7} C/m^{2}](https://tex.z-dn.net/?f=9.735%20%5Ctimes%2010%5E%7B-7%7D%20C%2Fm%5E%7B2%7D)
Thus, we can conclude that the charge density on each surface of the dielectric is
.
Answer:
![t=0.0107\ \text{s}](https://tex.z-dn.net/?f=t%3D0.0107%5C%20%5Ctext%7Bs%7D)
Explanation:
![x=10\cos(6t)](https://tex.z-dn.net/?f=x%3D10%5Ccos%286t%29)
Now ![x=8\ \text{cm}](https://tex.z-dn.net/?f=x%3D8%5C%20%5Ctext%7Bcm%7D)
Substituting the value of
in the equation we get
![8=10\cos6t](https://tex.z-dn.net/?f=8%3D10%5Ccos6t)
![\Rightarrow 0.8=\cos6t](https://tex.z-dn.net/?f=%5CRightarrow%200.8%3D%5Ccos6t)
![\Rightarrow \cos^{-1}0.8=6t](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ccos%5E%7B-1%7D0.8%3D6t)
the values here are used found in radians
![\Rightarrow t=0.0107\ \text{s}](https://tex.z-dn.net/?f=%5CRightarrow%20t%3D0.0107%5C%20%5Ctext%7Bs%7D)
So, at
the value of
.
It’s gonna be Oxygen ....