Answer:
Here you go now
0.25
or
1/4
Step-by-step explanation:
Hopefully this is correct!
- Unbrand -
Answer:
Length of diagonal is 7.3 yards.
Step-by-step explanation:
Given: The diagonal distance from one corner of the corral to the opposite corner is five yards longer than the width of the corral. The length of the corral is three times the width.
To find: The length of the diagonal of the corral.
Solution: Let the width of the rectangular garden be <em>x</em> yards.
So, the length of the diagonal is ![x+5](https://tex.z-dn.net/?f=x%2B5)
width of the rectangular corral is ![3x](https://tex.z-dn.net/?f=3x)
We know that the square of the diagonal is sum of the squares of the length and width.
So,
![(3x)^{2} +x^{2} =(x+5)^{2}](https://tex.z-dn.net/?f=%283x%29%5E%7B2%7D%20%2Bx%5E%7B2%7D%20%3D%28x%2B5%29%5E%7B2%7D)
![9x^{2} +x^{2} =x^{2}+10x+25](https://tex.z-dn.net/?f=9x%5E%7B2%7D%20%2Bx%5E%7B2%7D%20%3Dx%5E%7B2%7D%2B10x%2B25)
![9x^{2}-10x-25=0](https://tex.z-dn.net/?f=9x%5E%7B2%7D-10x-25%3D0)
![9x^{2}-10x-25=0](https://tex.z-dn.net/?f=9x%5E%7B2%7D-10x-25%3D0)
![x=\frac{-b\pm\sqrt{b^{2} -4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E%7B2%7D%20-4ac%7D%20%7D%7B2a%7D)
![x=\frac{10\pm\sqrt{(-10)^{2} -4(9)(-25)} }{2(9)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B10%5Cpm%5Csqrt%7B%28-10%29%5E%7B2%7D%20-4%289%29%28-25%29%7D%20%7D%7B2%289%29%7D)
![x=\frac{10\pm\sqrt{100}}{18}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B10%5Cpm%5Csqrt%7B100%7D%7D%7B18%7D)
Since, side can't be negative.
![x=\frac{5}{9}+\frac{5}{9}\sqrt{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%7D%7B9%7D%2B%5Cfrac%7B5%7D%7B9%7D%5Csqrt%7B10%7D)
Now, length of the diagonal is
Hence, length of diagonal is 7.3 yards.
Answer:
92%
Step-by-step explanation:
Answer:
1/3
Step-by-step explanation: