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Semenov [28]
3 years ago
6

The question is

Chemistry
1 answer:
SashulF [63]3 years ago
3 0

Answer:

4

Explanation:

because is has the greatest volt

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How many grams of h2 are needed to produce 10.78 g of nh3?
balu736 [363]
Ammonia is formed by a reaction between hydrogen and nitrogen as shown by the equation below.
N2(g) + 3H2(g) = 2NH3(g)
1 mole of ammonia contains 17 g
Therefore 10.78 g of ammonia are equivalent to 10.78/17 = 0.6341 moles
The mole ratio of hydrogen to ammonia is 3 : 2
Therefore, moles of hydrogen used will be  0.6341 × 3/2 = 0.9512 moles
1 mole of hydrogen is equivalent to 2 g
Thus, the mas of hydrogen will be 0.9512 moles × 2 = 1.9023 g
6 0
4 years ago
A shampoo has a pH of 8.59. What is the [H3O+] in the shampoo?
Cerrena [4.2K]

Answer:

2.57 e-9

Explanation:

The formula is H3O=10^-Ph

10^-8.59=2.57 e-9

6 0
3 years ago
What is the relationship between the kinetic energy of molecules in an object and the object's temperature?
Gennadij [26K]

Answer:

Explanation:

Temperature measures the average kinetic (or motion) energy of the particles within a substance.

6 0
3 years ago
A gold ring with a mass of 16g was dropped in the snow and its temperature dropped from 35°C to 0°C. How much heat was released
Luda [366]

Answer:

-72.8 joules

Explanation:

just finished the test

4 0
3 years ago
A gas mixture contains HBr, NO2, and C2H6 at STP.If a tiny hole is made in the container, which gas will effuse fastest?Which ga
MakcuM [25]

Explanation:

Molar mass of HBr = 81 g/mol

Molar mass of nitrogen dioxide gas = 46 g/mol

Molar mass of ethane = 30 g/mol

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

So, the gas with least molar mass will effuse out fastest from the container and that is ethane gas.

The formula for average kinetic energy is:

K.E=\frac{3}{2}kT

where,

k = Boltzmann’s constant = 1.38\times 10^{-23}J/K

T = temperature = 273.15 K ( at STP)

As we can see from the formula that kinetic energy depends upon only temperature of the gas molecule.

So, from this we can say that all the gas molecules have the same average kinetic energy at this temperature.

5 0
4 years ago
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