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3 years ago

Laura is skydiving when at a certain altitude she opens her parachute and

Physics

1 answer:

sukhopar [10]3 years ago

7 0

Answer:

Explanation:

The motion is under a constant velocity which means she has no acceleration.

So we can use,

Velocity = displacement/ time taken

Displacement = velocity× time taken

= 6.5×34 = 221m

We consider distance she fall as displacement as she doesn't change her direction.

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What is the wavelength of a wave that has a speed of 350 meters/second and a frequency of 140 hertzDoes sound travel faster in a

babymother [125]

Answer:

Wavelength of wave is 2.5 meters

Explanation:

Given that,

Speed of a wave, v = 350 m/s

Frequency of the wave, f = 140 Hz

The formula to find the speed of sound is given by :

$v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{350\ m/s}{140\ Hz}\\\\\lambda=2.5 m$

The speed of sound is more in higher temperature. At higher temperature, the molecules vibrate with more energy. As a result, sound travel faster in a warm room.

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3 years ago

A 62.0-kg skier is moving at 6.30 m/s on a frictionless, horizontal, snow-covered plateau when she encounters a rough patch 4.90

Klio2033 [76]

Here are the missing questions:
(a) How fast is the skier moving when she gets to the bottom of the hill?
(b) How much internal energy was generated in crossing the rough patch?
Part A
The initial kinetic energy of the skier is:
$E_{k0}=m\frac{v_0^2}{2}$
Part of this energy is then used to do work against the force of friction. Force of friction on the horizontal surface can be calculated using following formula:
$F_f=mg\mu$
The work is simply the force times the length:
$W_f=F_f\cdot L=mg\mu L$
So when the skier passes over the rough patch its energy is:
$E=E_{k0}-W_f$
When the skier is going down the skill gravitational potential energy is transformed into the kinetic energy:
$E_p=E_{k1}\\ mgh=E_{k1}$
So the final energy of the skier is:
$E_f=E_{k0}-W_f+E_{k1}\\ E_f=m\frac{v_0^2}{2}-mg\mu L+mgh=1856.86$J$
This energy is the kinetic energy of the skier:
$E_f=m\frac{v_f^2}{2}\\ v_f=\sqrt{\frac{2E_f}{m}}=7.74\frac{m}{s}$
Part B
We know that skier lost some of its kinetic energy when crossing over the rough patch. This energy is equal to the work done by the skier against the force of friction.
$E_{int}=W_f\\
E_{int}=mg\mu L=894.1$J$

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4 years ago

A meter stick is balanced at the 50 cm mark. You tie a 20 N weight at the 20 cm mark. Where should a 30 N weight be placed so th

vivado [14]

Answer:

20 cm to the right of the center or 20+50 = 70 cm from the left side.

Explanation:

The length of meter stick is 1 m = 100 cm

Balance point on 50 cm

From the center the 20 N weight is 50-20 = 30 cm

Torque is obtained when force is multiplied with the distance

As the force is conserved we have

$\dfrac{20}{30}\times 30=20\ cm$

The distance will be 20 cm to the right of the center or 20+50 = 70 cm from the left side.

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3 years ago

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irinina [24]

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3 years ago

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Blizzard [7]

Answer:

Explanation:

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3 years ago