Based on the length of the Ethernet cable and the mass, the tension in the cable can be found to be 80 N.
<h3>How much tension is in the cable?</h3>
The tension in the cable can be found as:
= 4 x mass x length x frequency
Solving for the frequency is:
= 1 / (0.800 / 4)
= 1 / 0.20
= 5.0 Hz
The tension is therefore:
= 4 x 0.20 x 4.00 x 5
= 80N
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Answer:
second lag
Explanation:
If in a cup game, a specified time limit is assigned to both teams to score high. If both teams are unable to score or if score of both the teams is equal then there is another second lag played where each team tries to score high. Even if in second lag both teams fail to score higher than other the last third lag is played or else game is declared draw.
Answer:
vf=94.4 m/s
Explanation:
acceleration is the final velocity minus initial velocity divided by time
a = (vf-vi)/t
Given:
a= 14.2 m/s^2
vi= 0 (at rest)
t = 6.6
Solve for vf
a = (vf-vi)/t
a*t=vf-vi
(14.2)*(6.6)=vf - 0
vf=94.4 m/s
Answer:
its 1
Explanation:
Several factors can increase the rate of a chemical reaction. In general, anything that increases the number of collisions between particles will increase the reaction rate, and anything that decreases the number of collisions between particles will decrease the chemical reaction rate.
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