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dimulka [17.4K]
3 years ago
10

Biomedical, electrical and civil engineering essay

Engineering
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

7th A good time for you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my replying sooner than later this month to you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my replying sooner than later this month to you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my replying sooner than later this month to you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my replying sooner than later this month to you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my

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Explanation:

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3 years ago
malott, m. e. (2003). paradox of organizational change: engineering organizations with behavioral systems analysis.
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1 year ago
A wooden pallet carrying 540kg rests on a wooden floor. (a) a forklift driver decides to push it without lifting it.what force m
kicyunya [14]

Answer:

The appropriate solution is "1481.76 N".

Explanation:

According to the question,

Mass,

m = 540 kg

Coefficient of static friction,

\mu_s = 0.28

Now,

The applied force will be:

⇒ F=\mu_s mg

By substituting the values, we get

       =0.28\times 540\times 9.8

       =1481.76 \ N

8 0
2 years ago
A 1000-turn coil of wire 1.0 cm in diameter is in a magnetic field that increases from 0.10 T to 0.30 T in 10 ms. The axis of th
ddd [48]

emf generated by the coil is 1.57 V

Explanation:

Given details-

Number of turns of wire- 1000 turns

The diameter of the wire coil- 1 cm

Magnetic field (Initial)= 0.10 T

Magnetic Field (Final)=0.30 T

Time=10 ms

The orientation of the axis of the coil= parallel to the field.

We know that EMF of the coil is mathematically represented as –

E=N(ΔФ/Δt)

Where E= emf generated

ΔФ= change inmagnetic flux

Δt= change in time

N= no of turns*area of the coil

Substituting the values of the above variables

=1000*3.14*0.5*10-4

=.0785

E=0.0785(.2/10*10-3)

=1.57 V

Thus, the emf generated is 1.57 V

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3 years ago
AVH
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