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Alexxx [7]
3 years ago
6

sample of CaCO3 was heated cause causing it to form CA Oh and CO2 gas solid CAO remains behind while does CO2 escaped to the atm

osphere. if caco3 weighed 612g and the caO weighed 343 g, how many grams of cO2 were formed in the reaction
Chemistry
1 answer:
OleMash [197]3 years ago
8 0

<u>Answer:</u> The mass of carbon dioxide formed in the reaction is 269 grams.

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The chemical equation for the decomposition of calcium carbonate follows:

CaCO_3\rightarrow CaO+CO_2

Let the mass of carbon dioxide be 'x' grams

We are given:

Mass of calcium carbonate = 612 grams

Mass of CaO = 343 grams

Total mass on reactant side = 612 g

Total mass on product side = [343 + x] g

So, by applying law of conservation of mass, we get:

612=343+x\\\\x=(612-343)=269g

Hence, the mass of carbon dioxide formed in the reaction is 269 grams.

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M(H₂SO₄) = 2·1 + 32 + 4·16 · g/mol.
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m(H₂SO₄) = 1,2 mol · 98 g/mol.
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8 0
4 years ago
Which body of water will have a greater influence on an area?
Andrei [34K]

Answer:

The correct option is A

Explanation:

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3 years ago
How can you tell if a compound is an acid or base?
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How many molecules of Oxygen are consumed if 24 molecules of Carbon Dioxide are produced?
Nat2105 [25]

Answer:

Explanation:

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From the reaction, it shows that mole ratio between C and O2 = 1 : 1.

So, 2 moles of C will stoichiometrically react with 2 moles of O2 to generate 2 moles of CO2.

Avogadro's law states that :"equal volumes of all gases, at the same temperature and pressure, have the same number of molecules i.e. 6.02 x 10^23 molecules/mole.

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3 years ago
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Explanation:

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