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Akimi4 [234]
4 years ago
13

A frog jumps vertically upward from a 20m tall building with an initial velocity of 10m/s. How high above the ground will the fr

og reach? What is its velocity as it hits the ground below?
Physics
1 answer:
Semenov [28]4 years ago
5 0
Consider the initial position of the frog (20 m above ground) as the reference position. All measurements are positive measured upward.
Therefore,
u = 10 m/s, initial upward velocity.
H = - 20 m, position of the ground.
g = 9.8 m/s², acceleration due to gravity.

Part (a)
When the frog reaches a maximum height of h from the reference position, its velocity is zero. Therefore
u² - 2gh = 0
h = u²/(2g) = 10²/(2*9.8) = 5.102 m
At maximum height, the frog will be 20 + 5.102 = 25.102 m above ground.

Answer: 25.1 m above ground

Part (b)
Let v = the velocity when the frog hits the ground. Then
v² = u² - 2gH
v² = 10² - 2*9.8*(-20) = 492
v = 22.18 m/s

Answer: The frog hits the ground with a velocity of 22.2 m/s

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4 years ago
____ is the thermal energy transfer that occurs from the motion of fluid in a liquid or gas.
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a transformer has 1,400 turns in the primary coil and 100 turns in the secondary coil. if the primary coil is connected to a 120
harkovskaia [24]

0.56 A is the current of the secondary coil.

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we know that ;

I ∝ 1/n;

where I IS CURRENT and n is NUMBER OF TURNS.

(I) secondary = X A

(n) secondary = 100

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USING THIS-----> I ∝ 1/n;

=>

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as the current in the transformer is inversely proportional to the number of turns so 0.56 A is the current in the secondary coil.

learn more about transformers-

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