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11Alexandr11 [23.1K]
3 years ago
5

When stress is added to plates they can diverge, converge, or slip past one another True or False

Chemistry
1 answer:
zmey [24]3 years ago
5 0
The answer is True i believe
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The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams o
earnstyle [38]

The amount of heat needed to vaporize the given amount of water is the product of the amount in grams and the latent heat of vaporization in cal per gram. That is,

                              H = (540 calories / gram)( 500 grams) = 270,000 cal

Thus, the heat needed is 270, 000 calories. The answer is letter C.

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8 0
3 years ago
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What is the molar mass of HBR
alexdok [17]

Answer:

Molar mass of bromine is equal to 80.9119

Explanation:

The molar mass of HBr is equal to the sum of atomic weight of  Bromine.

Atomic Weight of hydrogen is equal to 1.00794

Atomic Weight  of Bromine is equal to 79.904

Molar mass of Bromine

= Atomic Weight of hydrogen + Atomic Weight  of Bromine

Molar mass of Bromine  = 79.904 + 1.00794  = 80.9119

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3 years ago
2. Which organelle holds genetic information in the molecule DNA? A. vacuole B. cell membrane C. chromosome D. Golgi body
malfutka [58]
B.cell membrane is the answer
7 0
3 years ago
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Using the drop-down menus, label the parts of the rock<br> cycle.<br> A~<br> B~<br> C~<br> D~
enyata [817]

Answer:

A- Sediment

B-Metamorphic Rocks

C-Sedimentary

D-Erosion

Explanation:

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Question 23
Schach [20]

Answer:

Option B. 0.136 g

Explanation:

The balanced equation for the reaction is given below:

2AgNO3(aq) + 2NaOH(aq) —> Ag2O(s) + 2NaNO3(aq) + H2O(l)

Next, we shall determine the masses of AgNO3 and NaOH that reacted and the mass of Ag2O produced from the balanced equation. This is illustrated below:

Molar mass of AgNO3 = 108 + 14 + (16x3) = 170g/mol

Mass of AgNO3 from the balanced equation = 2 x 170 = 340g

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Molar mass of Ag2O = (108x2) + 16 = 232g/mol

Mass of Ag2O from the balanced equation = 1 x 232 = 232g

Summary:

From the balanced equation above,

340g of AgNO3 reacted with 80g of NaOH to produce 232g of Ag2O.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

340g of AgNO3 reacted with 80g of NaOH.

Therefore, 0.2g of AgNO3 will react with = (0.2 x 80)/340 = 0.047g of NaOH.

From the calculations made above, only 0.047g out of 0.2g of NaOH given, reacted completely with 0.2g of AgNO3. Therefore, AgNO3 is the limiting reactant and NaOH is the excess reactant.

Now, we can calculate the mass of Ag2O produced from the reaction of 0.2g of AgNO3 and 0.2g of NaOH.

In this case, we shall use the limiting reactant because it will produce the maximum yield of Ag2O as all of it is used up in the reaction.

The limi reactant is AgNO3 and the mass of Ag2O produced can be obtained as follow:

From the balanced equation above,

340g of AgNO3 reacted to produce 232g of Ag2O.

Therefore, 0.2g of AgNO3 will react to produce = (0.2 x 232)/340 = 0.136g of Ag2O.

Therefore, 0.136g of Ag2O was produced from the reaction.

8 0
3 years ago
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