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3 years ago

What are the two applications of electron beam welding

1 answer:

5 0

First of all, there are not just two applications that are solely applicable to the electron beam welding process. There are MANY.

Please visit out website at the URL below and you can click the "View Application" button under each listed Industry segment to view case studies of commonly EB welded applications.

https://www.ptreb.com/electron-beam-welding-applications

And for more general information on our welding process, we have an informational section you can peruse as well:

https://www.ptreb.com/electron-beam-welding-information

Good luck with your assignment- we are glad to hear they are teaching about EBW in high school!!!

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(PLEASE HELP ILL GIVE OUT BRAINLIEST) Mr. Hicks stands on top of the roof and drops water ball oons at passing students. He miss

notsponge [240]

Answer:

18.032m/s, 16.59m

Explanation:

Used to find the distance traveled

y=1/2gt^2, where y= vertical distance, g=acceleration due to gravity, and t=time

y=1/2*9.8*1.84^2

y=16.59m distance

Used to solve the final velocity before hitting the ground

vf=vo+at where vf=final velocity, vo=initial velocity, a=acceleeration, t=time

vf=0+9.8*1.84

vf=18.032m/s

4 0

3 years ago

Read 2 more answers

A solid block of copper, which is a good conductor, has a cavity in its interior. Within the cavity, insulated from the conducto

Nikolay [14]

Answer:

The charge on the outer surface of the block = -5.00 nC

The charge on the surface of the cavity (on the inner surface of the block) = -3.00 nC

Explanation:

The point charge within the cavity will induce a charge equal in magnitude and opposite in sign on the inside cavities of the copper block.

Charge of the point charge = 3.00 nC

Charge induced on the inner surface of the Copper block's cavity = -3.00 nC

Since the charge on a conductor should usually be neutral, the charge on the inner surface causes a charge equal in magnitude and also opposite in sign on the outer surface of the block; that is, 3.00 nC.

But this block already has an excess charge of -8.00 nC (which resides on the surface because excess charge for conductors reside on the surface of the conductors)

So, net charge on the outer surface of the Copper block = -8.00 + 3.00 = -5.00 nC.

Hope this Helps!!!

4 0

3 years ago

Suppose you are observing the interference pattern formed by a Michelson interferometer in a laboratory and a joking colleague h

Troyanec [42]

Answer:

Explanation:

In Michelson interferometer , two light waves from different directions are made to overlap so that fringes are formed on the screen due to interference . In it, two monochromatic and coherent light are made to overlap which have some path difference or phase difference. They form dark and bright fringes .

Now when a match stick is lit in the path of a wave , the fringes will disappear and an general illumination will be observed on the screen as the light from the lit match stick will not be coherent . Incoherent light can not form stable fringes.

7 0

3 years ago

A 40.0-mH inductor is connected to a North American electrical outlet (ΔVrms = 120 V, f = 60.0 Hz). Assuming the energy stored i

trasher [3.6K]

Explanation:

It is given that,

Inductance, $L=40\ mH=40\times 10^{-3}\ H$

RMS value of voltage, $v_{rms}=120\ V$

Frequency, f = 60 Hz

We need to find the energy stored at t = (1 /185) s. It is assumed that energy stored in the inductor is zero at t = 0. So,

The current flowing through the inductor is given by :

$I_t=\dfrac{V_o}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})$

$I_t=\dfrac{\sqrt{2} V_{rms}}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})$

$I_t=\dfrac{120\sqrt{2}}{2\pi f L}\ sin(2\pi f t-\dfrac{\pi}{2})$

$I_t=\dfrac{120\sqrt{2}}{2\pi\times 60\times 40\times 10^{-3}}\ sin(2\pi \times 60\times \dfrac{1}{185})-\dfrac{\pi}{2})$

$I_t=\dfrac{120\sqrt2}{15.07}\ sin(2\pi \times 60\times \dfrac{1}{185}-\dfrac{\pi}{2})$

I = 0.091 A

Energy stored in the inductor is, $U=\dfrac{1}{2}LI^2$

$U=\dfrac{1}{2}\times 40\times 10^{-3}\times (0.091)^2$

U = 0.000165 Joules

Hence, this is the required solution.

6 0

3 years ago

How polar bear can survive in the polar region

ladessa [460]

Answer:

Hey mate.....

Explanation:

This is ur answer...

Polar bears are well adapted for survival in the Arctic. Their adaptations include: a white appearance - as camouflage from prey on the snow and ice. thick layers of fat and fur - for insulation against the cold.

Hope it helps!

Brainliest pls!

Follow me! ◇

7 0

2 years ago