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blagie [28]
4 years ago
6

What are the two applications of electron beam welding

Physics
1 answer:
Georgia [21]4 years ago
5 0

First of all, there are not <u>just</u> two applications that are solely applicable to the electron beam welding process. There are MANY.

Please visit out website at the URL below and you can click the "View Application" button under each  listed Industry segment to view case studies of commonly EB welded applications.

https://www.ptreb.com/electron-beam-welding-applications

And for more general information on our welding process, we have an informational section you can peruse as well:

https://www.ptreb.com/electron-beam-welding-information

Good luck with your assignment-  we are glad to hear they are teaching about EBW in high school!!!

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Answer:

Acceleration of the car will be a=8m/sec^2

Explanation:

We have given that car starts from rest so initial velocity of the car u = 0 m/sec

And car traveled 400 m in 10 sec

So distance traveled by car s = 400 m

Time taken to compete this distance t = 10 sec

We have to find the acceleration of the car

From second equation of motion we know that s=ut+\frac{1}{2}at^2

So 400=0\times 10+\frac{1}{2}\times a\times 10^2

a=8m/sec^2

So acceleration of the car will be a=8m/sec^2

7 0
3 years ago
Convert 32 centimeters into inches. (1 in = 2.54 cm)
Nataly [62]

Answer: 32 centimeters is 12.5984 inches

Explanation:

8 0
3 years ago
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An 80-kg bungee jumper jumps off a bridge. Rubber bungee cords act as a large spring attaching the jumper to the bridge. A bear
inysia [295]

Answer:

The force is F_b =  216 \  N

Explanation:

From the question we are told that

   The  mass of the bungee jumper is  m  = 80 kg

    The spring constant is  k =  20 \  N/ m

    The extension of the rubber bungee cords is  x = 50 m

Generally the weight of the jumper is

      W =  m *  g

=>   W =  80 *  9.8

=>   tex]W =  784  \  N  [/tex]

Generally  the returning force of the rubber bungee cords is mathematically represented as

      F  =  k  *  x

=>     F  =  20   * 50

=>     F  =  1000 \  N

The force to be applied by the bear is

    F_b =  F -  W

=>    F_b =  100 -  784

=>  F_b =  216 \  N

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3 years ago
Once you have picked a standard by the very meaning of atandard it is invariable.
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Answer:

düz devam sağa dön bı tane Kabe var

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4 years ago
A 920 kg cannon fires a 3.5 kg shell at initial acceleration of 95 m/s^2. What is the cannon's recoil force?
Mice21 [21]

Answer:

The cannon recoils with a force of 332.5 N

Explanation:

By Newton's third law Recoil force on cannon = Force in shell.

Force in shell = Mass of shell x Acceleration of shell

Mass of shell = 3.5 kg

Acceleration of shell = 95 m/s²

Force in shell = 3.5 x 95 = 332.5 N

Recoil force on cannon = 332.5 N

So, the cannon recoils with a force of 332.5 N

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