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4 years ago

What are the two applications of electron beam welding

1 answer:

5 0

First of all, there are not <u>just</u> two applications that are solely applicable to the electron beam welding process. There are MANY.

Please visit out website at the URL below and you can click the "View Application" button under each listed Industry segment to view case studies of commonly EB welded applications.

https://www.ptreb.com/electron-beam-welding-applications

And for more general information on our welding process, we have an informational section you can peruse as well:

https://www.ptreb.com/electron-beam-welding-information

Good luck with your assignment- we are glad to hear they are teaching about EBW in high school!!!

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The container was lifted a height of 14 m

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Work done = Force X Distance

3 430 000J = Force X 14m

Force = 3 430 000J / 14m
= 245 000 N

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2 years ago

a carpenter hits a nail with a hammer. compared to the magnitude of the force the hammer exerts on the nail, the magnitude of th

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The exact same amount of force will be exerted but in opposite direction

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4 years ago

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Professor Sanchez believes that children acquire language through reinforcement from adults, especially their parents. He believ

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3 years ago

Please help! I especially need help with the second question but help with the first one would be most appreciated!

lara31 [8.8K]

Answer:

a) Team A will win.

b) The losing team will accelerate towards the middle line with 0.01 m/ $s^{2}$

Explanation:

Given that Team-A pulls with a force , $F_{1} = 50N$

and Team-B pulls with a force , $F_{1} = 45N$

∵ $F_{1} > F_{2}$

The rope will move in the direction of force $F_{1}$ .

∴ Team-A will win.

b) Considering both the teams as one system of total mass , $m = 246+253 = 499 kg$

Net force on the system , $F = F_{1} - F_{2}$ = 50-45 = 5N

Applying Newtons first law to the system ,

F = ma , where 'a' is the acceleration of the system.

Since , both the teams are connected by the same rope , their acceleration would be the same.

∴ 5 = 499×a

∴ a = 0.01 m/ $s^{2}$

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4 years ago

In a shipping yard, a crane operator attaches a cable to a 1240-kg shipping container and then uses the crane to lift the contai

Firdavs [7]

Answer:

Explanation:

Given

mass of ship =1240 kg

height=37 m

(a)Work done by Tension in cable+work done by gravity =0

Work done by gravity =change in potential energy of mass $=-1240\times 9.8\times 37=-449.624 kJ$

Thus work done by tension=449.624 kJ

(b)work done by force of gravity $=-mg\times h=-1240\times 9.8\times 37$ =-449.624 kJ

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3 years ago

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