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sasho [114]
2 years ago
7

At what height h above the ground does the projectile have a speed of 0.5v?

Physics
1 answer:
dedylja [7]2 years ago
3 0

Answer:height above ground at which projectile have velocity

0.5v is (0.0375v^2)

Explanation:

Using Vf = Vi - gt

Where Vf is final velocity

Vi is initial velocity

g is the acceleration due to gravity

t is the time taken

So, 0.5v = v - gt

t = 0.05v

Therefore height h = vt - 0.5gt^2

Subtitute t

h = 0.05v^2 - 0.0125v^2

h = 0.0375v^2

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Can someone help me?!!
Fantom [35]
<h2>Hello!</h2>

The answer is:

The first option, the force tending to lift Rover is equal to 14.5 N.

<h2>Why?</h2>

To calculate the force that is tending to lift Rover vertically, we need to calculate the vertical component force.

Since we know that the angle between the force and the ground is 29°, we can calculate the vertical component of the force using the following formula:

F_y=Force*Sin(29\°)

We are given that the force is equal to 30.0 N, so, calculating we have:

F_y=Force*Sin(29\°)

F_y=30N*Sin(29\°)=14.5N

Also, we can calculate the horizontal component of the force using the following formula:

F_x=Force*Cos(29\°)

F_x=30N*Cos(29\°)=26.24N

Hence, we have that the correct option is the first option, the force tending to lift Rover is equal to 14.5 N.

Have a nice day!

5 0
3 years ago
If jack was traveling at 100 miles in 2 hours what was his speed in miles per minute?
Ludmilka [50]

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Speed = (100 mi/2 hr)

Multiply by a fraction equal to 1 :

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Speed = (100 x 1 / 2 x 60) (mi-hr/hr-min)

Speed = (100 / 120) (mi / min)

Speed = 5/6 mi/min

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4 0
3 years ago
Momentum of the 2 kg mass moving with velocity 10 m/s is *
gulaghasi [49]
20 kg*m/s because there is 2 kg mass and 10 m/s so you can multiply.
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Explanation:

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Tasya [4]

the answer is static friction


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