(b) The cylinder shown in figure 2 is fitted with a freely sliding piston containing an ideal gas of mass 13g and volume 1.0×10⁴
cm⁵ . The tempreture of the gas is 25°C and it is initially at atmospheric pressure.
(i) The gas is heated to a Tempreture of 400°C . what is the new volume of the gas?
(i) The gas is heated to a Tempreture of 400°C . what is the new volume of the gas?
1 answer:
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Answer:
distance r from the uranium atom is 18.27 nm
Explanation:
given data
uranium and iron atom distance R = 44.10 nm
uranium atom = singly ionized
iron atom = doubly ionized
to find out
distance r from the uranium atom
solution
we consider here that uranium electron at distance = r
and electron between uranium and iron so here
so we can say electron and iron distance = ( 44.10 - r ) nm
and we know single ionized uranium charge q2= 1.602 × C
and charge on iron will be q3 = 2 × 1.602 × C
so charge on electron is q1 = - 1.602 × C
and we know F =
so now by equilibrium
Fu = Fi
=
put here k = and find r
=
r = 18.27 nm
distance r from the uranium atom is 18.27 nm
The speed of A and B immediately after collision is 5.28m/s
<u>Explanation:</u>
Mass of A is 6275kg
Speed of A is 6.5m/s
Mass of B is 5155kg
Speed of B is 3.8m/s
Track is frictionless.
A and B stick together.
speed of attached A and B = ?
mₐsₐ + mᵇsᵇ = (mₐ + mb) s
Therefore, The speed of A and B immediately after collision is 5.28m/s
Answer:
28.2 m/s
Explanation:
The range of a projectile launched from the ground is given by:
where
v is the initial speed
g = 9.8 m/s^2 is the acceleration of gravity
is the angle at which the projectile is thrown
In this problem we have
d = 81.1 m is the range
is the angle
Solving for v, we find the speed of the projectile: