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Select all that apply. The rate law for the reaction 2NO(g) + CU(g) rightarrow 2NOCl(g) is given by R = k[NO][Cl2] If the follow

Daniel [21]

Answer:

a. 2nd order reaction.

b. The first step is the slow step.

Explanation:

r = k[NO][Cl₂]

a. The reaction is first-order in [NO] and first-order in [Cl₂], so it is second-order overall.

b. The first step is the slow step, because it predicts the correct rate law.

c. is wrong. Doubling [NO] would double the rate, because the reaction is first-order in [NO].

d. is wrong. Cutting [Cl₂] in half would halve the rate, because the reaction is first-order in [Cl₂].

e. is wrong. The molecularity is two, because two particles are colliding.

f. is wrong. Both steps are bimolecular.

4 0

4 years ago

[06.01]The same amount of heat is removed from 2 kg of water and from 1 kg of water starting at the same temperature. What will

liq [111]

<span>Answer: The 1 kg of water will reach the lowest temperature
</span>
Both of the objects is water so their specific heat should be same. The heat removed from the 2kg of water which is 2 times of mass than the 1kg water. Since the heat removed, both of their temperatures will drops. But 2kg water temperature drops will be half of 1kg water.

6 0

3 years ago

Find the "natural" equilibrium concentration of NO in air in units of molecules/cm3 .

Vedmedyk [2.9K]

Answer:

6400 molecules / cm^3

Explanation:

10.6*10^-16 mol/L * 6.022*10^23 molecules/mol * 1 L / 1000 cm^3 * 1 / 100 L = 6400 molecules / cm^3

6 0

3 years ago

2 Use the chart to answer the question. Solubility Curves of Various Salts 180 160 140 120 100 80 KNO3 in g NaCl in g KCl in g A

VMariaS [17]

According to the information in the graph, it can be inferred that the amount of solute that will precipitate out of solution at 20°C is 130 grams.

<h3>How to calculate the amount of solute that precipitates out of solution?</h3>

To calculate the amount of solute that precipitates out of solution we must identify the solute data at 80°C and 20°C and identify the difference as shown below:

Quantity of solute at 80°C: 170 grams.
Quantity of solute at 20°C: 40 grams.

170 grams - 40 grams = 130 grams

According to the above, the amount of solute that will precipitate out of solution due to the change in temperature is 130 grams of KNO3.

Note: This question is incomplete because the graph is missing. Here is the graph

Learn more about solute in: brainly.com/question/7932885

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7 0

2 years ago

The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sample o

adoni [48]

Answer:

550 m/s

Explanation:

The average molecular speed (v) is the speed associated with a group of molecules on average. We can calculate it using the following expression.

$v = \sqrt{\frac{3 \times R \times T}{M} }$

where,

R: ideal gas constant

T: absolute temperature

M: molar mass of the gas

We can use the info of argon to calculate the temperature for both samples.

$T = \frac{v^{2} \times M}{3 \times R} = \frac{(391m/s)^{2} \times 39.95g/mol}{3 \times 8.314J/k.mol} = 2.45 \times 10^{5} K$

Now, we can use the same expression to find the average molecular speed in a sample of Ne gas.

$v = \sqrt{\frac{3 \times R \times T}{M} } = \sqrt{\frac{3 \times (8.314J/k.mol) \times 2.45 \times 10^{5}K }{20.18g/mol} } = 550 m/s$

7 0

3 years ago