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Nookie1986 [14]
3 years ago
11

The heat of fusion for water at its normal freezing or melting temperature is L=333 kJ/kg. How much water remains unfrozen after

50.2 kJ is transferred as heat from 260 g of liquid water initially at its freezing point? ...?
Chemistry
2 answers:
shutvik [7]3 years ago
8 0
50.2 kJ = 333 kJ/kg * mass of watermass of water is 0.15075075075075075075075075075075 kgtherefore mass of unfrozen water is 0.10924924924924924924924924924925 kg
Amiraneli [1.4K]3 years ago
5 0
<span>50.2 kJ = 333 kJ/kg * mass of water mass of water is 0.15075075075075075075075075075075 kg therefore mass of unfrozen water is 0.10924924924924924924924924924925 kg</span>
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Pls help and show work!!!
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