I was flung towards the atmosphere. Slowly but surely, I made my way inside. On my way there, I began to heat up. I began to vibrate rapidly, and I noted it happened as I entered the atmosphere. I think it was because we sped up so much, but I can't say for sure because I'm an air particle... However, I do know that I am now a heated air particle due to friction and movement from entering the atmosphere. I think I'll cool down on my descent, I don't know that I can get much hotter than this.
It is important to use the same balance throughout the entire experiment since the calibration of each balance is not the same and changing balances could result in a systematic error.
There are three types of errors that could affect the results of the experiment. The effect of random or indeterminate errors is hard to predict, its effect on the results of the experiment could be different every time. The second type of error is the systematic or determinate error, which causes a shift in results in a specific direction. The last type of error in an experiment is human error.
The type of error that could be related to the use of different balances throughout the experiment is the systematic error. Instruments could be a source of error especially if they are poorly calibrated. Also, analytical balances are calibrated differently which may result in inaccuracy in the weighing of chemicals.
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A balanced chemical reaction obeys the law of conservation of mass, because the same number of atoms of each element must appear on both sides of the equation for the reaction … , and in any actual reaction, the same exact atoms will be found on both sides of the equation.
Explanation:
both iron and sulphur in FeS2 undergo a change in oxidation state.
O2° -->2O degree2- Total decrease = 2×2=4
So, 4FeS2+11O2 --> 2Fe2O3+8 SO2
Hence, balanced
2 Na₂CO₃ + 2 CuSO₄ + H₂O → CuCO₃.Cu(OH)₂ + 2 Na₂SO₄ + CO₂
Malachite molar mass = 221.1 g / mol
So 2 moles CuSO₄ produce 1 mole of malachite
so 1.5 mole CuSO₄ produce (0.75) mole malachite
Mass of malachite = 0.75 mole * 221.1 g/ mol = 165.83 g
