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Anarel [89]
3 years ago
7

A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the rms value of the cur

rent in this circuit is 0.600 A, what is the impedance of this circuit?
Physics
1 answer:
klemol [59]3 years ago
8 0

Answer:

The impedance of this circuit is 200 ohm.

Explanation:

Given that,

rms voltage = 120 v

Frequency = 60.0 Hz

rms current = 0.600 A

We need to calculate the impedance

Using formula of impedance

Z=\dfrac{V_{rms}}{I_{rms}}

Where, V_{rms} = rms voltage

I_{rms} = rms current

Z= impedance

Put the value into the formula

Z=\dfrac{120}{0.600}

Z=200\ Omega

Hence, The impedance of this circuit is 200 ohm.

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1) Num sistema isolado tenho 4 tipos de corpos diferentes. A, B, C e D. A está em equilíbrio térmico com B. B está em equilíbrio
liberstina [14]

Answer:

Yes.

Explanation:

Yes, this system transmitting energy between your bodies because everybody is in thermal equilibrium with other body. Thermal equilibrium occurs when there is same amount of thermal energy is gained by the body and same amount of energy lost by the body so there is no increase or decrease occur in the thermal energy of each body so we can say that the system transmitting energy between the bodies.

8 0
3 years ago
An empty glass beaker has a mass of 103 g. When filled with water, it has a total mass of 361g.
aivan3 [116]

Answer:

0.96 gcm¯³

Explanation:

From the question given above, the following data were obtained:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of beaker + oil = 351 g

Density of water = 1 gcm¯³

Density of cooking oil =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of water =?

Mass of water = (Mass of beaker + water) – (Mass of empty beaker)

Mass of water = 361 – 103

Mass of water = 258 g

Next, we shall determine the volume of the beaker. This can be obtained by calculating the volume of water in the beaker.

Density of water = 1 gcm¯³

Mass of water = 258 g

Volume of water =?

Density = mass /volume

1 = 258 / volume

Cross multiply

1 × volume = 258

Volume of water = 258 cm³

Thus the volume of the beaker is 258 cm³.

Next, we shall determine the mass of the cooking oil. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + oil = 351 g

Mass of cooking oil =?

Mass of cooking oil = (Mass of beaker + oil) – (Mass of empty beaker)

Mass of cooking oil = 351 – 103

Mass of cooking oil = 248 g

Finally, we shall determine the density of the cooking oil. This can be obtained as follow:

Mass of cooking oil = 248 g

Volume of the beaker = 258 cm³

Density of cooking oil =?

Density = mass / volume

Density = 248 / 258

Density of cooking oil = 0.96 gcm¯³

7 0
3 years ago
This graph shows the change in the force of gravity as distance increases. The graph will never reach zero, which suggests that​
kumpel [21]

Answer:

Gravity can never be zero.

Explanation:

The graph shows that the force of gravity is always present despite the amount of distance, indicating that gravity will never be 0. Note, however, that gravity can be extremely small as the distance increases. The limit of the force of gravity as the distance approaches infinity is 0, but never actually touches this value.

7 0
3 years ago
Two blocks connected by a string are pulled across a horizontal surface by a force applied to one of the blocks, as shown to the
Harman [31]

Answer:

Explanation:The Mass Of The Left Block M1 = 1.3 Kg And The Mass Of The Right Block M2 = 3.1 Kg. The Angle Between The String And The Horizontal Is ... (10%) Problem 8: Two blocks connected by a string are pulled across a horizontal surface by a ... m m, 50% Part (a) Write an equation for the magnitude of the force exerted by the ...

6 0
3 years ago
A sharpening stone, also called whetstone, is used for sharpening ferrous tools. A round whetstone is mounted on the shaft of an
iVinArrow [24]

Answer:

3.2 kJ

Explanation:

Since torque, τ = Iα where I = moment of inertia of round whetstone = 4.0 kgm² and α = angular acceleration of round whetstone.

So, α = τ/I

Given that τ = 20 Nm,

α = τ/I

α = 20 Nm/4.0 kgm²

α = 5 rad/s²

Using the equation for rotational motion, the angular velocity, ω = ω₀ + αt

where ω₀ = initial angular speed of round whetstone = 0 rad/s (since it starts from rest), ω = final angular speed of round whetstone, α = angular acceleration of round whetstone = 5 rad/s² and t = time of rotation = 8 s.

So, substituting the values of the variables into the equation, we have

ω = ω₀ + αt

ω = 0 rad/s + 5 rad/s² × 8s

ω = 0 rad/s + 40 rad/s

ω = 40 rad/s

So, its kinetic energy change ΔK = K₂ - K₁ = 1/2Iω² - 1/2Iω₀²

where K₁ = initial kinetic energy of round whetstone = 0 J (since the stone starts from rest) and K₂ = final kinetic energy of round whetstone after 8 s

Substituting the values of the variables into the equation, we have

K₂ - K₁ = 1/2Iω² - 1/2Iω₀²

K₂ - 0 J = 1/2 × 4.0 kgm² × (40 rad/s)² - 1/2 × 4.0 kgm² × (0 rad/s)²

K₂ = 2.0 kgm² × 1600 rad²/s² - 0 J

K₂ = 3200 kgm²rad²/s² - 0 J

K₂ = 3200 J

K₂ = 3.2 kJ

3 0
3 years ago
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