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Lostsunrise [7]
3 years ago
11

Identify all graphs that represent motion at

Physics
1 answer:
Vesna [10]3 years ago
3 0

Answer:

Good Luck!

Follow Me

<h2><u><em>D</em></u></h2>

Explanation:

3) For a displacement time graph, straight line denotes constant speed. For a velocity time graph, the graph parallel to time axis denotes constant speed. Hence, the correct option is a) and d).

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What is the orbital period in years of a planet with a semi major axis of 35 au
mezya [45]

Answer:

Orbital period of the planet will be 207.06 year                      

Explanation:

We have given the planet have the semi major axis as 35 au

We have to find the orbital period of the planet

From Keplar's third  law there is relation between the orbital period and semi major axis which is t T^2=R^3

So T^2=35^3

T^2=42875

T=207.06year

So orbital period of the planet will be 207.06 year

6 0
3 years ago
1) Radiation from the sun can be deflected or contained by
earnstyle [38]

Answer:

b

Explanation:

light colors deflect ligjt

7 0
3 years ago
How does Cassie fell about the forest ?in song of the trees
Naily [24]
Send a pic or something so more people understand
7 0
3 years ago
We divide the electromagnetic spectrum into six major categories of light, listed below. Rank these forms of light from left to
makkiz [27]

electromagnetic spectrum is consisting of many frequency range which is from gamma rays to radio waves

they are of various wavelength and different energy levels

minimum wavelength will occurs at Gamma rays

and maximum wavelength at Radio waves

the list of increasing order of wavelength is as following

Gamma rays < X rays < Ultraviolet < Visible Light < Infrared Waves < Radio Waves

so least to maximum order is

1. Gamma rays

2. X rays

3 Ultraviolet

4 Visible light

5 Infrared waves

6 Radio waves

5 0
3 years ago
A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr
max2010maxim [7]

Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is  \phi _2  = 1.57 \  rad

Explanation:

From the question we are told that

    The wavelength of the spherical wave is  \lambda =  2.0 \ mm =  \frac{2}{1000} = 0.002 \ m

    The first radius  is  r_1  = 4.0 \ mm  = \frac{4}{1000}  = 0.004 \ m

     The phase at that instant is  \phi _1 = \pi \ rad

     The second radius is  r_2  = 3.5 \ mm  = \frac{3.5}{1000}  = 0.0035 \ m

Generally the phase difference is mathematically represented as

          \Delta  \phi =  \phi _2 -  \phi _1

this can also be expressed as

         \Delta \phi =  \frac{2 \pi }{\lambda } (r_2 - r_1 )

So we have that

   \phi _2 -  \phi _1 =   \frac{2 \pi }{\lambda } (r_2 - r_1 )

substituting values

     \phi _2 -  \pi =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 )

    \phi _2  =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 ) +   3.142

   \phi _2  = 1.57 \  rad

7 0
3 years ago
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