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3 years ago

A 10kg block is Pulled along a horizontal

Physics

2 answers:

sweet [91]3 years ago

8 0

Answer:

I cant understand the question well but i will tell u how to solve it

first apply f = ma eqaulation vertically...then u will get an r = mg which means normal upward force = weight of the object (to find weight multiply mass by 9.81)

$f = ma \\ r - mg = 0 \\ r = mg$

after that use friction eqaution which is

$f = \mu \times r$

(mu) is the coefficient of friction and (r) is the vertical normal force then by substituting value you can get an answer for the friction

the use

$f = ma \\ f \cos(37) - fr = ma$

by using the above eqaution you can get an answer for acceleration...

hope you can understand...

Leviafan [203]3 years ago

6 0

Answer:

Explanation:

I hate these kinds of problems, luckily I can't understand how much the kinetic friction is for this , the words are all mixed around. and don't read well. Maybe this went through a translator program? My suggestion draw the free body diagram. so you can see where the forces are, and how they are acting. getting the free body diagram right.. usually makes these problems pretty straight forward. just do the steps and you get the answer.

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What happens when the mass of an object is greter

Paul [167]

The acceleration goes up.

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3 years ago

The quantity of charge q (in coulombs) that has passed through a surface of area 2.00 cm2 varies with time

Makovka662 [10]

Explanation:

We have,

Surface area, $A=2\ cm^2=0.0002\ m^2$

The current varies wrt time t as :

$q(t) = 4t^3 + 5t + 6$

(a) At t = 2 seconds, electrical charge is given by :

$q(t) = 4t^3 + 5t + 6\\\\q(2) = 4(2)^3 + 5(2) + 6\\\\q=48\ C$

(b) Current is given by :

$I=\dfrac{dq}{dt}\\\\I=\dfrac{d(4t^3 + 5t + 6)}{dt}\\\\I=12t^2+5$

Instantaneous current at t = 1 s is,

$I=12(1)^2+5=17\ A$

Current density is given by electric current per unit area.

$J=\dfrac{I}{A}\\\\J=\dfrac{(12t^2+5)}{0.0002}\\\\J=5000(12t^2+5)\ A/m^2$

Therefore, it is the required explanation.

7 0

3 years ago

1 7.1.2 Quiz: Electrostatics

Veseljchak [2.6K]

Answer:

charge and distance

Explanation:

The electric force between the two particles are calculated using the formular:

F = kQ₁Q₂ / d²

where:

F = force.

k= Coulomb's law constant.

Q1 and Q2 are the charges.

d= distance.

the equation above is called Coulomb's law.

It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance.

so the correct option is charge and distance.

5 0

2 years ago

A circuit with a resistance of 25 ohms is carrying a current of 2

-BARSIC- [3]

The heat developed can be calculated using the power rules as follows:

P = I x V = I^2 x R

First solution is to use the given values of I and R as follows:
P = I^2 x R = (2)^2 x 25 = 4 x 25 = 100 watt

Second solution is to use ohm's law to get V, then substitute to get the power as follows:
V = I x R = 2 x 25 = 50 volts
Power = V x I = 50 x 2 = 100 watt

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3 years ago

Un acróbata de 60 kg realiza un acto de equilibrio sobre un bastón. El extremo del bastón, en contacto con el piso, tiene un áre

vivado [14]

Answer:

Pressure, $P=6.39\times 10^6\ Pa$

Explanation:

A 60 kg acrobat performs a balancing act on a cane. The end of the cane, in contact with the floor, has an area of 0.92 cm2. Calculate the pressure the cane exerts on the floor (neglect the weight of the cane).

We have,

Mass of acrobat, m = 60 kg

The end of the cane, in contact with the floor, has an area of, $A=0.92\ cm^2=0.92\times 10^{-4}\ m^2$

It is required to find the the pressure the cane exerts on the floor. Pressure exerted by an object is defined as the force acting per unit its area. Its formula is written as :

$P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{60\times 9.8}{0.92\times 10^{-4}}\\\\P=6.39\times 10^6\ Pa$

So, the pressure the cane exerts on the floor is $6.39\times 10^6\ Pa$ .

3 0

3 years ago