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2 years ago

A 10kg block is Pulled along a horizontal

Physics

2 answers:

sweet [91]2 years ago

8 0

Answer:

I cant understand the question well but i will tell u how to solve it

first apply f = ma eqaulation vertically...then u will get an r = mg which means normal upward force = weight of the object (to find weight multiply mass by 9.81)

$f = ma \\ r - mg = 0 \\ r = mg$

after that use friction eqaution which is

$f = \mu \times r$

(mu) is the coefficient of friction and (r) is the vertical normal force then by substituting value you can get an answer for the friction

the use

$f = ma \\ f \cos(37) - fr = ma$

by using the above eqaution you can get an answer for acceleration...

hope you can understand...

Leviafan [203]2 years ago

6 0

Answer:

Explanation:

I hate these kinds of problems, luckily I can't understand how much the kinetic friction is for this , the words are all mixed around. and don't read well. Maybe this went through a translator program? My suggestion draw the free body diagram. so you can see where the forces are, and how they are acting. getting the free body diagram right.. usually makes these problems pretty straight forward. just do the steps and you get the answer.

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Natalija [7]

Answer:

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Explanation:

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2 years ago

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Leokris [45]

Answer:

Explanation:

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2 years ago

How many seconds in a day? A hole day.

gizmo_the_mogwai [7]

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3 years ago

The resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is:a) 180 d

r-ruslan [8.4K]

Answer:

0 degrees

Explanation:

Let $F_1\ and\ F_2$ are two forces. The resultant of two forces acting on the same point is given by :

$F_R=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos\theta}$

Where $\theta$ is the angle between two forces

When $\theta=0$ i.e. when two forces are parallel to each other,

$F_R=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos(0)}$

$F_R=\sqrt{F_1^2+F_2^2+2F_1F_2}$

When $\theta=90^{\circ}$ i.e. when two forces are parallel to each other,

$F_R=\sqrt{F_1^2+F_2^2+F_1F_2\ cos(90)}$

$F_R=\sqrt{F_1^2+F_2^2}$

When $\theta=180^{\circ}$ i.e. when two forces are parallel to each other,

$F_R=\sqrt{F_1^2+F_2^2+F_1F_2\ cos(180)}$

$F_R=\sqrt{F_1^2+F_2^2-2F_1F_2}$

It is clear that the resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is 0 degrees. Hence, this is the required solution.

8 0

2 years ago

A hot copper pan is dropped into at tub of hot water. If the water's temperature rises, what happens to the temperature of the p

choli [55]

Explanation:

As it is given that hot pan of copper is dropped into a tub of hot water and the temperature of water rises. This means that heat from the pan has been released and this heat is gained by water.

As a result, temperature of copper pan has decreased and this decrease will continue till the time temperature of both copper pan and water will reach the same temperature.

As thermal energy is defined as the energy in which when two objects come in physical contact with each other then no exchange of heat energy will take place.

Thus, we can conclude that when temperature of both copper pan and water will be equal then it means that both of them has reached thermal equilibrium.

8 0

2 years ago

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