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Alexxx [7]
3 years ago
7

A supersaturated solution is one which A. has less solute dissolved than the solution should hold at that temperature. B. has mo

re solvent dissolved than the solution should hold at that temperature. C. has more solute dissolved than the solution should hold at that temperature. D. has less solvent dissolved than the solution should hold at that temperature.
Physics
1 answer:
Anna35 [415]3 years ago
3 0

Answer:

Option C is correct

Explanation:

A supersaturated solution is one that has more solute dissolved than the solution should hold at that temperature.

Examples include carbonated water, sugar syrup, honey.

A solution of a chemical compound can be dissolved in heated water to prepare a supersaturated solution. A solution becomes supersaturated as its temperature is changed.

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A 980 kg roller coaster cart is traveling along a track at 17 m/s before it rolls down a 30 m tall hill (Point A). What will be
MrRissso [65]

The kinetic energy halfway the hill is 2.86\cdot 10^5 J

Explanation:

If there are no friction forces acting on the cart, we can apply the law of conservation of energy: the mechanical energy of the cart (which is the sum of potential energy + kinetic energy) must be conserved. So we can write:

U_A +K_A = U_B + K_B

where

U_A=mgh_A is the initial potential energy, at point A, with

m = 980 kg (mass of the cart)

g=9.8 m/s^2 (acceleration of gravity)

h_A = 30 m (height at point A)

K_A=\frac{1}{2}mv_A^2 is the initial kinetic energy, at point A , with

v_A=17 m/s (velocity at point A)

U_B=mgh_B is the final potential energy, at point B, where

h_B = 15 m (height at point B)

K_B=\frac{1}{2}mv_B^2 is the final kinetic energy, at point B, where

v_B is the velocity at point B

Here we are interested in finding K_B, so by re-arranging the equation and substituting we find:

K_B = U_A+K_B-U_B = mg(h_A-h_B)+\frac{1}{2}mv_A^2=(980)(9.8)(30-15)+\frac{1}{2}(980)(17)^2=2.86\cdot 10^5 J

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

8 0
3 years ago
3.5-m-diameter merry-go-round is rotating freely with an angular velocity of 0.78 rad/s . Its total moment of inertia is 1710 kg
Monica [59]
I dont get the question your asking
4 0
3 years ago
Two objects, one with a mass of and the other with a force of 30.0kg experience a gravitational force of attraction of 7.50 * 10
nydimaria [60]

Answer:

Explanation:

The formula for this is

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the gravitational constant, m1 is the mass of one object and m2 is the mass of the other object. We are looking for r, the distance between the centers of their masses.

Filling in:

7.5*10^{-8}=\frac{6.67*10^{-11}(90.0)(30.0)}{r^2} and moving things around to solve for r:

r=\sqrt{\frac{6.67*10^{-11}(90.0)(30.0)}{7.5*10^{-8}} } Doing all that and rounding to the 3 sig fig's you need gives us a distance of 1.55 m

8 0
3 years ago
When light in vacuum is incident at the polarizing angle (Brewster's angle) on a certain glass slab, the angle of refraction is
marysya [2.9K]

Answer:

Explanation:

θ( p ) + θ( r ) = 90  

θ (r) = angle of refraction and θ ( p ) is polarising angle.

given θ ( r ) = 31.8

θ ( p ) = 90 - 31.8 = 58.2 degree

ii ) Tanθ ( p ) = n ( refractive index ) = Tan 58.2 = 1.6

3 0
3 years ago
If you we're in charge of designing a wire to cart electricity across your city, state or provide, which of the following proper
OLEGan [10]

Answer:

It should be fibre optic cable , buried underground

4 0
3 years ago
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