Answer:
T= 633.51 x 10⁻²⁸ N.m
Explanation:
Given that
r= 4.52 x 10⁻¹¹ m
v= 2.8 x 10⁶ m/s
B= 6.29 mT
We know that charge on electron Q
Q= 1.6 x 10⁻¹⁹ C
The time period t
t=2πr / v
Now by putting the values
t=(2 x π x 4.52 x 10⁻¹¹ ) / (2.80 x 10⁶)
t= 10.13 x 10⁻¹⁷ s
So current I
I = Q/t
I=(1.6 x 10⁻¹⁹)/(10.13 x 10⁻¹⁷)
I= 1.57 mA
The torque T given as
T = I A B
A= π x (4.52 x 10⁻¹¹) ² m²
A= 64.15 x 10⁻²² m²
T = I A B
T = 1.57 x 10⁻³ x 64.15 x 10⁻²² x 6.29 x 10⁻³ M.m
T= 633.51 x 10⁻²⁸ N.m
Answer:
<h3>2,321.62Joules</h3>
Explanation:
The formula for calculating workdone is expressed as;
Workdone = Force * Distance
Get the force
F = nR
n is the coefficient of friction = 0.5
R is the reaction = mg
R = 46 ( 9.8)
R = 450.8N
F = 0.5 * 450.8
F = 225.4N
Distance = 10.3m
Get the workdone
Workdone = 225.4 * 10.3
Workdone = 2,321.62Joules
<em>Hence the amount of work done is 2,321.62Joules</em>
One's body movement to the side when a car makes a sharp turn.
Tightening of seat belts in a car when it stops quickly.
A ball rolling down a hill will continue to roll unless friction or another force stops it.
Men in space find it more difficult to stop moving because of a lack of gravity acting against them.
N, or Neutons are a common way to measure force
