All categories

3 years ago

Since acids are so corrosive they are not found anywhere in the human body true/false

Physics

2 answers:

pantera1 [17]3 years ago

5 0

the answer is in fact True

s2008m [1.1K]3 years ago

3 0

False. Our digestive tract, in particular the stomach, contains hydrochloric acid to aid digestion. The stomach's lining protects the rest of your body from effects of such acids. This is just one example of many acids contained in our bodies.

You might be interested in

A wire with a mass of 1.14 g/cm is placed on a horizontal surface with a coefficient of friction of 0.200. The wire carries a cu

anzhelika [568]

Answer: $B=0.0162T$

Explanation:

let this sign be ∅ (titha in degrees)

let coefficient of friction of 0.200 be u

and i be current i= 1.41A

mass m=1.14g/cm m=0.0114g/m

To find the magnetic field from the north will be:

tan ∅= u

∅= $tan^{-1}(0.200$

∅=11.3°

The direction:

i L*B cos(∅)= umg

divide both by iLcos(∅) to find B

B= $\frac{umg}{iBcos(∅)}$ where m= $\frac{m}{L}$

B= $\frac{u(m/L)g}{icos(∅)}$

B= $\frac{0.200*0.0114*9.81}{1.41*cos(11.3)}$

$B=0.0162T$

7 0

3 years ago

A vertical spring with a spring constant of 420 N/m is mounted on the floor. From directly above the spring, which is unstrained

mixas84 [53]

Answer:

19.53 cm

Explanation:

The computation of the height is as follows:

Here we applied the conservation of the energy formula

As we know that

P.E of the block = P.E of the spring

m g h = ( 1 ÷ 2) k x^2

where

m = 0.15

g = 9.81

k = 420

x = 0.037

So now put the values to the above formula

(0.15) (9.81) (h) = 1 ÷2 × 420 × (0.037)^2

1.4715 (h) = 0.28749

h = 0.19537 m

= 19.53 cm

3 0

3 years ago

A boy is pulling a wagon with a force of 70.0 N directed at an angle of 30 degrees above the horizontal. What are the x and y co

bogdanovich [222]

Answer:

x component is 60.60 N and y component is 35 N ⇒ answer A

Explanation:

A boy is pulling a wagon with a force of 70.0 N directed at an angle

of 30 degrees above the horizontal then,

$F_{x}$ is the horizontal component of the force in the direction

of positive part of x-axis

$F_{y}$ is the vertical component of the force force in the direction

of positive part of y-axis

The x component of the force $F_{x}$ is the force multiplied by

cos(30)°

The y component of the force $F_{y}$ is the force multiplied by

sin(30)°

→ The x component $F_{x}$ = F cos(30)

→ The x component $F_{x}$ = 70 cos(30) = 60.60 N

→ The y component $F_{y}$ = F sin(30)

→ The y component $F_{y}$ = 70 sin(3) = 35 N

<em>x component is 60.60 N and y component is 35 N</em>

7 0

4 years ago

Steel is very stiff, and the Young's modulus for steel is unusually large, 2.0×1011 N/m2. A cube of steel 25 cm on a side suppor

TEA [102]

Answer:

Force (normal) = 833.85 N Compression = 1.67 x 10⁻⁸ m

Explanation:

Given data Young's Modulus (Y) = 2 x 10¹¹ N/m², Length of one side of cube = 25 cm = 0.25 m, mass of load = 85 kg

Normal force is the force exerted upon an object that is in contact with another stable object. This force would be applied by the surface onto the object in the same vector and is used to keep the object stable while it rests on a surface.

We know from Newton's Second Law that

F = ma where m is the mass and a is the acceleration (<em>in this case due to gravity</em>) hence, the normal opposing force to the load applied by the surface would be equal to the force applied on the surface by the weight of the load on the surface, So

F (normal) = M (load) x a = 85 x 9.81 = 833.85 N

Compression is the change in length of an object by the exertion of force upon it. Using the Young's Modulus formula we can find this change in the cube of steel. The Young's Modulus is given by

Y = (F/A)/(ΔL/L), where Y is the Young's Modulus, F is the Force being applied on the object, A is the cross sectional area on which the said force is applied, ΔL is the change in length due to said force being applied and L is the original Length of the side of the cross sectional area.

Solving this for ΔL, we can re- arrange the equation

ΔL = (F x L)/(Y x A) since area of square is L x L we can simplify the equation to get

ΔL = (F)/(Y x L), substitute the values

ΔL = (833.85)/(2 x 10¹¹ x 0.25) = 1.67 x 10⁻⁸m

6 0

4 years ago

How to convert 7500kilometers to meters

Kazeer [188]

Answer:

7500000 metres

Explanation:

1 kilometre = 1000 metres

so 7500 kilometres would equal to 7500000 metres

7 0

3 years ago