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Irina18 [472]
3 years ago
12

If you wanted to know the location of a vehicle that ran out of gas after taking a zigzag route through the city, which quantity

would be
most useful?

a. the vehicle's speed

b. the vehicle's distance

c. the vehicle's direction

d. the vehicle's displacement
Physics
1 answer:
Papessa [141]3 years ago
8 0

Explanation:

the vehicles displacement, since displacement deals with position

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If my cylinder of air lasts 60 minutes while I am at the surface breathing normally, assuming all else is the same, how long wil
AfilCa [17]

Answer:

Explanation:

Let the volume of air be V. at atmospheric pressure, that is 10⁵  Pa

At 20 m below surface pressure will be

atmospheric pressure + hdg

10⁵ + 20 x 9.8 x 1000 = 2.96 x 10⁵Pa

At this pressure volume V becomes V/ 2.96  

This volume will last 1/2.96 times  time that is 60/2.96 = 20.27 minutes.

8 0
3 years ago
An electric motor uses
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6 0
4 years ago
700%
aleksklad [387]

Answer:

Approximately 22.9 seconds.

Explanation:

A sound wave travel 340m in 1 sec

For 7800m it will travel;

\frac{7800}{340} * 1 = 22.94117647 sec

It will take approximately 22.9 seconds.

4 0
4 years ago
A 1.0 kg ball is thrown into the air with an initial veocity of 30. m/s. how much kinetic energy does the ball have?
rosijanka [135]
1/2 mv2 so you get 450j
8 0
3 years ago
‼️‼️ Please help, urgent ‼️‼️ (check photo)
Alex787 [66]

Answer: The force constant k is 10600 kg/s^2

Step by step:

Use the law of energy conservation. When the elevator hits the spring, it has a certain kinetic and a potential energy. When the elevator reaches the point of still stand the kinetic and potential energies have been transformed to work performed by the elevator in the form of friction (brake clamp) and loading the spring.

Let us define the vertical height axis as having two points: h=2m at the point of elevator hitting the spring, and h=0m at the point of stopping.

The total energy at the point h=2m is:

E_{tot}=E_{kin}+E_{pot}\\E_{tot}= \frac{1}{2}mv^2+mg\Delta h = \frac{1}{2}2000 kg 4^2\frac{m^2}{s^2}+2000kg\, 9.8\frac{m}{s^2}2m=55200\,kg\frac{m^2}{s^2}

The total energy at the point h=0m is:

E_{tot}=E_{kin}+E_{pot}+Work=0+0+ Work\\E_{tot} =F_{friction}\Delta h+\frac{1}{2}k (\Delta h)^2=17000N\cdot 2m+\frac{1}{2}k\cdot 2^2 m^2

The two Energy values are to be equal (by law of energy conservation), which allows us to determine the only unknown, namely the force constant k:

17000N\cdot 2m+\frac{1}{2}k\cdot 2^2 m^2 = 55200 \,kg\frac{m^2}{s^2}\\k = \frac{55200-34000}{2}\,\frac{kg}{s^2}=10600\frac{kg}{s^2}

5 0
3 years ago
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