We can determine a planet's orbital period and separation from its star using any detection method. The transit method can yield sizes, whereas the astrometric and doppler approaches can provide minimum masses.
We can calculate average density by combining the transit and doppler approaches. Numerous physical properties, including the semi-major axis, stellar mass, star radius, planet radius, eccentricity, and inclination, are calculated from these observable data. The mass of the planet is also calculated using the star's combined radial velocity readings.
List briefly the planetary characteristics that, in theory, can be detected with the present detection techniques. We can determine a planet's orbital period and separation from its star using any detection method. The transit method can yield sizes, whereas the astrometric and doppler approaches can provide minimum masses.
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Answer:
25.8 rad/s
Explanation:
C = circumference of the hollow sphere = 0.749 m
r = radius of the sphere
Circumference of the hollow sphere is given as
C = 2π r
0.749 = 2 (3.14) r
r = 0.12 m
m = mass of the basketball = 0.624 kg
Moment of inertia of basketball is given as
I = 5.99 x 10⁻³ kg-m²
w = angular speed
KE = Kinetic energy of the ball = 1.99 J
Kinetic energy of the ball is given as
KE = (0.5) I w²
1.99 = (0.5) (5.99 x 10⁻³) w²
w = 25.8 rad/s
Answer:
digital signals one non-obvious example of a digital signal is a hard disk. Discrete time signals are defined for a discrete set of values, like the samples of a continuous time signal, while digital signals are inherently digital, like the number that crosses a certain bridge every hour.
Explanation:
Analog signals for example, and aneroid barometer uses rotary position as the signal to conveyed by an analog signal, often such a signal is a measured response to changes in physical phenomena, such as sound, light, temperature, position, or pressure.
Answer: 5 Amperes
Explanation:
Current in the circuit = ?
Voltage in the circuit = 10Volts
Resistance = 2 Ω (Ω is the symbol for ohms, the unit of resistance)
Apply the formula:
Voltage = Current x Resistance
i.e V = IR
10V = I x 2 Ω
I = 10V / 2 Ω
I = 5 Amperes
Thus, the current in the circuit is 5 Amperes
