Answer:
There is no sufficient evidence to reject the company's claim at the significance level of 0.05
Step-by-step explanation:
Let
be the true mean weight per apple the company ship. We want to test the next hypothesis
vs
(two-tailed test).
Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by
which is normally distributed. The observed value is
. The rejection region for
is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.
Using the normal distribution, the area underneath the shaded region <u>between the two z-scores</u> is given by:
C. 0.6766.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
Hence, for this problem, the area is the <u>p-value of z = 0.75 subtracted by the p-value of z = -1.3</u>.
Looking at the z-table, the p-values are given as follows:
Then:
0.7734 - 0.0968 = 0.6766.
Which means that option C is correct.
More can be learned about the normal distribution at brainly.com/question/15181104
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Step-by-step explanation:
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Step-by-step explanation:
