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RideAnS [48]
4 years ago
11

Which is an acid-conjugate base pair?

Chemistry
2 answers:
taurus [48]4 years ago
8 0

I’m not sure if you were looking for a definition or examples so I’ll give you both.

Definition: a conjugate acid is a chemical compound formed by the reception of a proton by a base. You could say it is a base with a hydrogen ion added to it. Also, a conjugate vase is what is left over after an acid has donated a proton during any chemical reaction.

Examples:

Sulfuric Acid (H2SO4) is an acid because it donates H+ to the water. It becomes the hydrogen sulfate ion (HSO-4) which is the conjugate vase if sulfuric acid.

Ammonia (NH3) is a base because it accepts H+ from water to come it’s conjugate acid, the ammonium ion (NH+4)

shusha [124]4 years ago
4 0

Answer:

A conjugate acid formed by accepting proton (H+) by a base—in other words, it is a base with a hydrogen ion added to it. On the other hand, a conjugate base is what is left over after an acid has donated a proton during a chemical reaction. Hence, a conjugate base is a species formed by the removal of a proton from an acid.

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Lead will float in water.
Fed [463]

Actually, no. While their mass may be the same (1kg), the volume of lead is a lot smaller than that of feathers. As there is the same mass stuffed in a smaller space, it must be denser. The density of water is 1 g/cm3, so if the density of the lead is more than 1g/cm3, it has to sink

7 0
3 years ago
Read 2 more answers
if it takes 54 mL of 0.1 NaOH to neutralize 125 mL of an HCL solution, what is the concentration of HCL?
alexira [117]

Answer:

0.0432 M

Explanation:

We are given;

Volume of NaOH as 54 mL

Molarity of NaOH as 0.1 M

Volume of HCl as 125 mL

We are required to determine the concentration of HCl

Step 1; We write a balanced equation for the reaction between NaOH and HCl

The balanced equation is given by;

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

Step 2: Determine the number of moles of NaOH

Moles = Volume × molarity

Therefore;

Moles of NaOH = 0.054 L × 0.1 M

                          = 0.0054 Moles

Step 3: We use the mole ratio to determine the moles of HCl

From the equation;

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

Thus; moles of HCl = 0.0054 moles

Step 4: Determine the concentration of HCl

We know that;

Molarity = Moles ÷ Volume

Therefore;

Molarity of HCl = 0.0054 moles ÷ 0.125 L

                         = 0.0432 M

Therefore, the concentration of HCl is 0.0432 M

6 0
3 years ago
In the uncatalyzed reaction N2O4 (g) ⇌ 2 NO2 (g) the pressure of the gases at equilibrium are PN2O4 = 0.377 atm and PNO2 = 1.56
larisa86 [58]

Answer:

The pressures will remain at the same value.

Explanation:

A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the or slows down the rate of a chemical reaction.

While a catalyst affects the rate, it is noteworthy that it has no effect on the equilibrium position of the chemical reaction. A catalyst works by creating an alternative pathway for the reaction to proceed. Most times, it decreases the activation energy needed to kickstart the chemical reaction.

Hence, we know that it has no effect on the equilibrium position. Factors affecting equilibrium position includes, temperature and concentration of reactants and products( pressure in terms of gases).

The reactants and the products here are gaseous, and as such pressure affects the equilibrium position. Now, we have established that the equilibrium position is unaffected. And as such the pressure affecting it does not change.

Thus, we have established that the pressure of the products and reactants are unaffected and as such they remain at their value unaffected.

8 0
4 years ago
GIVEN BRAINLIEST
Alla [95]

C :)

I know this is right, I learned about this last year so I would really appreciate a brainliest

have a good day bud :)

5 0
3 years ago
How many moles of AIC3 are there in 1,119.972 g ?
Alchen [17]

Answer:

it is 8.40189 moles of AlCl3

mole = mass/molar mass

mole= 1119.972/133.34

6 0
3 years ago
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