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3 years ago

Which is an acid-conjugate base pair?

Chemistry

2 answers:

taurus [48]3 years ago

8 0

I’m not sure if you were looking for a definition or examples so I’ll give you both.

Definition: a conjugate acid is a chemical compound formed by the reception of a proton by a base. You could say it is a base with a hydrogen ion added to it. Also, a conjugate vase is what is left over after an acid has donated a proton during any chemical reaction.

Examples:

Sulfuric Acid (H2SO4) is an acid because it donates H+ to the water. It becomes the hydrogen sulfate ion (HSO-4) which is the conjugate vase if sulfuric acid.

Ammonia (NH3) is a base because it accepts H+ from water to come it’s conjugate acid, the ammonium ion (NH+4)

shusha [124]3 years ago

4 0

Answer:

A conjugate acid formed by accepting proton (H+) by a base—in other words, it is a base with a hydrogen ion added to it. On the other hand, a conjugate base is what is left over after an acid has donated a proton during a chemical reaction. Hence, a conjugate base is a species formed by the removal of a proton from an acid.

You might be interested in

the movement of molecules from an area of low concentration to an area of high concentration occurs in what transport?

solmaris [256]

Movement of molecules from an area of higher concentration to one of lower concentration is called Diffusion

4 0

3 years ago

6. A balloon filled with air has a volume of 3.25 L at 30°C. It is placed in a freezer at

Viefleur [7K]

Answer:

2.82 L

T₁ = 303 K

T₂ = 263 K

The final volume is smaller.

Explanation:

Step 1: Given data

Initial temperature (T₁): 30 °C

Initial volume (V₁): 3.25 L

Final temperature (T₂): -10 °C

Final volume (V₂): ?

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

T₁: K = 30°C + 273.15 = 303 K

T₂: K = -10°C + 273.15 = 263 K

Step 3: Calculate the final volume of the balloon

Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 3.25 L × 263 K/303 K = 2.82 L

7 0

3 years ago

What is the formula of haso4

ladessa [460]

Explanation:

The structure of Ferrarrisite Ca5(HAs O4)2(AsO4)2

8 0

3 years ago

A sample of N2O3(g) has a pressure of 0.046 atm . The temperature (in K) is then doubled and the N2O3 undergoes complete decompo

iogann1982 [59]

Answer:

0.184 atm

Explanation:

The ideal gas equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R the constant of the gases, and T the temperature.

So, the sample of N₂O₃ will only have its temperature doubled, with the same volume and the same number of moles. Temperature and pressure are directly related, so if one increases the other also increases, then the pressure must double to 0.092 atm.

The decomposition occurs:

N₂O₃(g) ⇄ NO₂(g) + NO(g)

So, 1 mol of N₂O₃ will produce 2 moles of the products (1 of each), the n will double. The volume and the temperature are now constants, and the pressure is directly proportional to the number of moles, so the pressure will double to 0.184 atm.

5 0

3 years ago

Silver sulfadiazine burn-treating cream creates a barrier against bacterial invasion and releases antimicrobial agents directly

trapecia [35]

Answer : The mass of silver sulfadiazine produced can be, 71.35 grams.

Solution : Given,

Mass of $Ag_2O$ = 25.0 g

Mass of $C_{10}H_{10}N_4SO_2$ = 50.0 g

Molar mass of $Ag_2O$ = 231.7 g/mole

Molar mass of $C_{10}H_{10}N_4SO_2$ = 250.3 g/mole

Molar mass of $AgC_{10}H_{9}N_4SO_2$ = 357.1 g/mole

First we have to calculate the moles of $Ag_2O$ and $C_{10}H_{10}N_4SO_2$ .

$\text{ Moles of }Ag_2O=\frac{\text{ Mass of }Ag_2O}{\text{ Molar mass of }Ag_2O}=\frac{25.0g}{231.7g/mole}=0.1079moles$

$\text{ Moles of }C_{10}H_{10}N_4SO_2=\frac{\text{ Mass of }C_{10}H_{10}N_4SO_2}{\text{ Molar mass of }C_{10}H_{10}N_4SO_2}=\frac{50.0g}{250.3g/mole}=0.1998moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Ag_2O(s)+2C_{10}H_{10}N_4SO_2(s)\rightarrow 2AgC_{10}H_9N_4SO_2(s)+H_2O(l)$

From the balanced reaction we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 1 mole of $Ag_2O$

So, 0.1998 moles of $C_{10}H_{10}N_4SO_2$ react with $\frac{0.1998}{2}=0.0999$ moles of $Ag_2O$

From this we conclude that, $Ag_2O$ is an excess reagent because the given moles are greater than the required moles and $C_{10}H_{10}N_4SO_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgC_{10}H_9N_4SO_2$

From the reaction, we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 2 mole of $AgC_{10}H_9N_4SO_2$

So, 0.1998 mole of $C_{10}H_{10}N_4SO_2$ react with 0.1998 mole of $AgC_{10}H_9N_4SO_2$

Now we have to calculate the mass of $AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=\text{ Moles of }AgC_{10}H_9N_4SO_2\times \text{ Molar mass of }AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=(0.1998moles)\times (357.1g/mole)=71.35g$

Therefore, the mass of silver sulfadiazine produced can be, 71.35 grams.

8 0

3 years ago