1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga nikolaevna [1]
3 years ago
10

Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

amount. The threshold limit is 2.0 x 10^-11 g per liter of air. If the current price of 50 g of vanillin is $112, determine the cost to supply enough vanillin so that the aroma could be detected in a large aircraft hangar with a volume of 5.0 x 10^7 ft^3.
Chemistry
1 answer:
balu736 [363]3 years ago
5 0

Answer:

Cost to supply enough vanillin is 3.2\$

Explanation:

Threshold limit of vanillin in air is 2.0\times 10^{-11}g per litre means there should be 2.0\times 10^{-11}g of vanillin in 1L of air to detect aroma of vanillin.

1ft^{3}=28.32L

So, 5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L

So amount of vanillin should be present to detect = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g

As cost of 50 g vanillin is 112\$ therefore cost of  (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)gvanillin = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$

You might be interested in
Magnesium burns with a very bright light. When the flame goes out, a White powder is left behind. what is the word equation for
melisa1 [442]
When magnesium is burned, it reacts with oxygen in air not with the fire. The fire is the energy needed for the reaction to happen. Magnesium reacts with oxygen forming magnesium oxide. The light emitted from the reaction is because the reaction produced a lot of heat.
6 0
3 years ago
An enzyme is a catalyst used by living things to promote and regulate chemical reactions. What is the most likely enzyme for the
dem82 [27]
I’m going to guess but B?
5 0
3 years ago
4. The picture shows a full moon.
Anuta_ua [19.1K]

Answer:

A full moon occurs when the Moon appears as a complete circle in the sky.

Explanation:

- We see it as a full orb because the whole of the side of the Moon facing the Earth is lit up by the Sun's rays.

- The moon shows no visible light of its own, so we only see the parts of the moon that are lit up by other objects.

6 0
2 years ago
Read 2 more answers
Explain how the mid-ocean ridge supports<br> the theory of sea floor spreading.<br> help plzzz:(
Sedaia [141]
The ridge of mid ocean b is the answer hope this helps
4 0
3 years ago
Someone please help will mark as brainliest
stich3 [128]

Answer:

A. 2Fe + 3Cl2 --> 2FeCl3

B. 2Fe + 3O2 --> 2Fe2O3

C. C4H10O + 4O2 --> 4CO2 + 5H2O

D. C7H16 + 11O2 --> 7CO2 + 8H2O

Explanation:

7 0
3 years ago
Other questions:
  • The website of a popular stargazers club notes that on Wednesday the moon will rise at 6:23 PM and set at 6:12 PM on Thursday. W
    15·2 answers
  • If you have a yellow light bulb and a blue one, which emits light of higher frequency?
    8·1 answer
  • If energy Is written on the product side of a chemical reaction, does it indicate that the reaction is endothermic or exothermic
    13·2 answers
  • PLEASE HELP!!! PLEASE.
    10·1 answer
  • Fill in the blank with the correct number to balance the equation: 4Cr + 3O2 → ___Cr2O3. (Enter only a whole number.)
    12·2 answers
  • 1 arsenic atom is 6.24 times heavier than one carbon atom (12) thus arsenic has the Atomic mass of what ?
    14·1 answer
  • Please help
    10·2 answers
  • 5.0 mL of 0.050 M Ba(NO3)2 M and 100.0 mL of 0.10 M KIO3 are added together in a 250 mL erlenmeyer flask. In this problem, ignor
    10·1 answer
  • Are sperm and egg cells exact copies of the plant cell
    8·1 answer
  • Once a peptide has been formed between the amino acid attached to the trna in the p site and the amino acid associated with the
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!