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olga nikolaevna [1]
3 years ago
10

Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

amount. The threshold limit is 2.0 x 10^-11 g per liter of air. If the current price of 50 g of vanillin is $112, determine the cost to supply enough vanillin so that the aroma could be detected in a large aircraft hangar with a volume of 5.0 x 10^7 ft^3.
Chemistry
1 answer:
balu736 [363]3 years ago
5 0

Answer:

Cost to supply enough vanillin is 3.2\$

Explanation:

Threshold limit of vanillin in air is 2.0\times 10^{-11}g per litre means there should be 2.0\times 10^{-11}g of vanillin in 1L of air to detect aroma of vanillin.

1ft^{3}=28.32L

So, 5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L

So amount of vanillin should be present to detect = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g

As cost of 50 g vanillin is 112\$ therefore cost of  (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)gvanillin = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$

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If the statement is true, select True. If it is false, select False.
defon

Answer:

False, since boiling is a physical change of state. Although it is at 100°C, it is not a chemical property.

Explanation:

Hope this helped!

5 0
3 years ago
A hypothetical element consists of four isotopes. Use the information below to calculate the average atomic volume mass of the e
Keith_Richards [23]

Answer:

104.969 amu.

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Mass of A = 107.977 amu

Abundance (A%) = 0.1620%

Isotope B:

Mass of B = 106.976 amu

Abundance (B%) = 1.568%

Isotope C:

Mass of C = 105.974 amu

Abundance (C%) = 47.14%

Isotope D:

Mass of D = 103.973 amu

Abundance (D%) = 51.13%

Average atomic mass =?

The average atomic mass of the element can be obtained as follow:

Average atomic mass = [(Mass of A × A%) /100] + [(Mass of B × B%) /100] + [(Mass of C × C%) /100] + [(Mass of D × D%) /100]

Average atomic mass = [(107.977 × 0.1620)/100] + [(106.976 × 1.568)/100] + [(105.974 × 47.14)/100] + [(103.973 × 51.13)/100]

= 0.175 + 1.677 + 49.956 + 53.161

= 104.969 amu

Therefore, the average atomic mass of the element is 104.969 amu.

8 0
3 years ago
A mixture of 50.0 mL of ammonia gas and 60.0 mL of oxygen gas react. If all the gases are at the same temperature and pressure,
fredd [130]

Answer:

72.0 mL of steam is formed.

Explanation:

The reaction is :

4 NH_{3} + 5O_{2} \rightarrow 4NO+6H_{2} O

You can treat coefficient of compounds as amount of volume used.

Therefore for 4 mL of ammonia 5 mL of oxygen is used to form 4 mL of nitric oxide gas and 6 mL of steam.

For 1 mL of ammonia \frac{5}{4} (=1.25) mL of oxygen is used to form \frac{4}{4} (=1) mL of nitric oxide gas and \frac{6}{4} (=1.5) mL of steam.

OR

Just transform the chemical equation by dividing the whole equation by 4 so that the coefficient of NH_{3} become one like this

NH_{3} + \frac{5}{4} O_{2} \rightarrow \frac{4}{4}NO+\frac{6}{4}H_{2} O

We don't know which one will be completely exhausted and which one will be left so we have to consider two cases :

<em>1.  </em><em>Assume ammonia to be completely exhausted</em>

For 50 mL of ammonia 50 \times \frac{5}{4} (= 62.5) mL of oxygen is needed. But we have just 60 mL of oxygen so this assumption is false.

2.  <em>Assume oxygen to be completely exhausted</em>

For 60 mL of oxygen only 60 \times \frac{4}{5} (=48) mL of ammonia is needed. In this case we have sufficient amount of ammonia. So this case is true.

60\times\frac{4}{5}NH_{3} + 60\ O_{2} \rightarrow 60\times\frac{4}{5}NO+60\times\frac{6}{5}H_{2} O\\\\48NH_{3} + 60\ O_{2} \rightarrow 48NO+72H_{2} O

Now we know that during complete reaction 48 mL of ammonia and 60 mL of oxygen is used which will form 60 \times \frac{4}{5} (= 48) mL of nitic oxide gas and 60 \times \frac{6}{5} (= 72) mL of steam.

Therefore <em>72 mL of steam </em>is formed.

5 0
3 years ago
Read 2 more answers
Find the boiling point?<br> 100. g of C2H6O2 dissolved in 200 g of H2O?
aleksklad [387]

Answer:

The correct answer is 104.13ºC

Explanation:

When a solute is added to a solvent, the boiling point of the solvent (Tb) increases. That is a colligative property. The increment in Tb (ΔTb)  is given by the following expression:

ΔTb = Tb - Tbº= Kb x m

Where Tb and Tbº are the boiling points of the solvent in solution and pure, respectively; Kb is a constant and m is the molality of the solution.

In this problem, the solvent is water (H₂O). It is well known that water has a boiling point of 100ºC (Tb). The value of Kb for water is 0.512ºC/m. So, we have to calculate the molality of the solution (m):

m = moles of solute/Kg solvent

The solute is C₂H₆O₂ and we have to calculate the number of moles of this component by dividing the mass into the molecular weight (Mw):

Mw(C₂H₆O₂)= (2 x 12 g/mol) + (6 x 1 g/mol) + (2 x 16 g/mol)= 62 g/mol

⇒ moles of C₂H₆O₂ = mass/Mw = 100 g/(62 g/mol) = 1.613 moles

Now, we need the mass of solvent (H₂O) in kilograms, so we divide the grams into 1000:

200 g x 1 kg/1000 g = 0.2 kg

Finally, we calculate the molality as follows:

m = 1.613 moles of C₂H₆O₂/0.2 kg = 8.06 moles/kg = 8.06 m

The increment in the boiling point will be:

ΔTb = Kb x m = 0.512ºC/m x 8.06 m = 4.13ºC

So, the boiling point of pure water (Tbº=100ºC) will increase in 4.13ºC:

Tb= 100ºC+4.12ºC= 104.13ºC

5 0
3 years ago
Use molecular orbital theory to determine whether f22+ is paramagnetic or diamagnetic.
Alexxandr [17]

We have to know whether F₂²⁺ is paramagnetic or diamagnetic.

F₂²⁺ is paramagnetic.

If number of unpaired electron in any species is equal to zero, the species is diamagnetic and the species contains unpaired electrons, then the species is paramagnetic.

The magnetic property can be explained using molecular orbital theory.

Total number of electron present in   F₂²⁺ is equal to 16 (i.e, 9+9-2). From the molecular orbital electronic configuration, number of electrons present in pi orbitals present is equal to 2.

So,  F₂²⁺ is paramagnetic.

7 0
3 years ago
Read 2 more answers
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