Dipole moment can be defined as the product of separation of the ends of the dipole and the magnitude of the charges
The correct answer to this question is this one:
Assuming all the barium bromide dissolved (which it should), the concentration of BaBr2 in solution should be zero: it should all dissociate into Ba+2 and 2Br- ions.
Turn those grams of BaBr2 into moles of BaBr2, then divide by the volume to get the concentration.
Recognize that every formula unit of BaBr2 has one ion of Ba+2, and 2 ions of Br-1. That means that when this substance dissociates, you'll get one concentration of Ba+2 ions, and a concentration of Br- ions TWICE as large. Whatever the concentration of Ba+2 ions is that you calculate, double it for the conentration of the Br-1 ion.
Answer:
Sodium chloride is formed when sodium atoms interact with chlorine atoms. When this occurs, sodium will donate an electron (which is a negatively-charged particle) to chlorine. This makes sodium slightly positive and chlorine slightly negative.
Opposite charges attract, right? So then, sodium ions will attract chloride ions and form an ionic bond. By the way, chloride is the term used to designate the anion form of chlorine. The result is a crystallized salt that has properties that are different from the two parent elements (sodium and chlorine). The chemical formula for sodium chloride is NaCl, which means that for every sodium atom present, there is exactly one chloride atom.
The chemical formula for ammonium carbonate is (NH₄)₂CO₃ .
It shows that one mole of ammonium carboonate contains two mole of ammonium ion that is NH₄⁺ .
Number of moles of ammonium carbonate , n=
Given mass of the ammonium carbonate=0.557 g
Molar mass of the ammonium carbonate= 96.086 g/mol
Number of moles of ammonium carbonate,
=0.0057 mol (NH₄)₂CO₃
0.0057 mol (NH₄)₂CO₃=0.0057×2 of NH₄⁺
=0.0114 of NH₄⁺
Answer
is: Ksp for AB₂ is 2.06·10⁻¹⁰.<span>
Chemical reaction: AB</span>₂(s) → Aˣ⁺(aq) + 2Bⁿ⁻(aq).
<span>
s(AB</span><span>₂) =
3,72·10⁻⁴ M.</span><span>
s(AB</span>₂) =
s(Aˣ⁺).
s(Bⁿ⁻) =
2s(AB₂).
Ksp(AB₂) = s(Aˣ⁺) ·
(s(Bⁿ⁻))².<span>
Ksp</span>(AB₂) = 3,72·10⁻⁴ ·
(7,44·10⁻⁴)².
Ksp(AB₂)= 2,06·10⁻¹⁰.