<span>Answer: Burrhus Frederic Skinner's Operant Conditioning.
</span><span>B.F. Skinner believed that to understand behavior, in the best way, is to look at the root causes or reasons of an action and its outcomes.
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Skinner proposes the Law of Effect-Reinforcement. Here,he differentiated the positively reinforced behavior or the strengthened behavior, the negatively reinforced behavior (removal of the unpleasant experience), and weakened behavior because of punishment.
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In positive reinforcement, behavior is strengthened through providing an outcome, an effect that an individual finds rewarding. Negative reinforcement also strengthens behavior because the unpleasant experience was removed. Punishment on the other hand is an opposite to reinforcement. Instead of increasing the response, it eliminates it or weakens it.
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Assume the snow is uniform, and horizontal.
Given:
coefficient of kinetic friction = 0.10 = muK
weight of sled = 48 N
weight of rider = 660 N
normal force on of sled with rider = 48+660 N = 708 N = N
Force required to maintain a uniform speed
= coefficient of kinetic friction * normal force
= muK * N
= 0.10 * 708 N
=70.8 N
Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.
Answer:
A) 
B) 
C) 
Explanation:
Given:
- mass of flywheel,

- diameter of flywheel,

- rotational speed of flywheel,

- duration for which the power is off,

- no. of revolutions made during the power is off,

<u>Using equation of motion:</u>



Negative sign denotes deceleration.
A)
Now using the equation:


is the angular velocity of the flywheel when the power comes back.
B)
Here:

Now using the equation:


is the time after which the flywheel stops.
C)
Using the equation of motion:


revolutions are made before stopping.
Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :


F = 0.607 N
(b) Area of wall, 
Let P is the average pressure on that area. It is given by :


P = 0.202 Pa
Hence, this is the required solution.
120 is your answer. 120 mL = 120 cm^3