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taurus [48]
3 years ago
8

A first number plus twice a second number is 5.twice the first number plus the second totals 31.find

Mathematics
1 answer:
givi [52]3 years ago
8 0
So if I understand this correctly, this would look something like this:


A first number

let's call it x

 plus twice a second number

let's call the second number y:

x+2y=5

 is 5.

this means that x=5-2y!


twice the first number plus the second totals 31.

2x+y=31

from the last one, i know that y=31-2x

and i can insert it into the first equation:

So i know that x=5-2y

and that

2x+y=31
i will substitute x here

2(5-2y)+y=31

remove the bracket

10-4y+y=31


10-3y=31

remove 10 from both sides

-3y=21

then

y=-7

and
x=5-2(-7)=5+14=19



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Answer:

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Step-by-step explanation:

7a-17 = 4a +1 ; Subtract 4a from both sides

3a - 17 = 1 ; Add 17 to both sides

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Alex73 [517]

Answer:

d=1

Step-by-step explanation:

\frac{-3d}{d^2-2d-8} +\frac{3}{d-4} =\frac{-2}{d+2}

Lets factor the denominator d^2 -2d-8

d^2 - 2d - 8 = (d-4)(d+2)

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Now make the denominators same

LCD: (d-4)(d+2)

\frac{-3d}{(d-4)(d+2)} +\frac{3(d+2)}{(d-4)(d+2)} =\frac{-2(d-4)}{(d+2)(d-4)}

Denominators are same on both sides

So equate the numerators

-3d +3(d+2) = -2(d-4)

-3d +3d +6 = -2d +8

6 = -2d + 8

subtract 8 on both sides

-2 = -2d

So d=1




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3 years ago
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A 2-column table with 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, positive 1, positive 2. The
S_A_V [24]

The rate of change of the linear function represented by the table is 3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The standard linear equation is in the form:

y = mx + b

Where m is the rate of change and b is the y intercept.

From the table, using the point (0, -7) and (2, -1):

m = [-1 - (-7)] / (2 - 0) = 3

The rate of change of the linear function represented by the table is 3

Find out more on equation at: brainly.com/question/2972832

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Divide that number by 12 for the answer
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3 years ago
Write the equation of the line parallel to 4x-5y=2 and passing through point (0,0)
kotykmax [81]

k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1\cdot m_2=-1\\\\k\ ||\ l\iff m_1=m_2

We have:

4x-5y=2\ \ \ \ |-4x\\\\-5y=-4x+2\ \ \ \ |:(-5)\\\\y=\dfrac{4}{5}x-\dfrac{2}{5}\to m_1=\dfrac{4}{5}\\\\l:y=m_2x+b\\\\k\ \prep\ l\Rightarrow\dfrac{4}{5}m_2=-1\ \ \ \ |\cdot\dfrac{5}{4}\\\\m_2=-\dfrac{5}{4}

l:y=-\dfrac{5}{4}x+b

The line l is passing through point (0, 0). Substitute the coordinates of the point to the equation of a line l:

0=-\dfrac{5}{4}\cdot0+b\to b=0

y=-\dfrac{5}{4}x\ \ \ \ |\cdot4\\\\4y=-5x\ \ \ \ |+5x\\\\5x+4y=0

<h2>Answer: 5x + 4y = 0</h2>
8 0
3 years ago
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