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Novosadov [1.4K]
3 years ago
10

I need help! In an equilibrium reaction with a Keq of 1 × 108 A. products are favored. B. the reaction is nonspontaneous. C. the

reaction is endothermic. D. reactants are favored.
Chemistry
2 answers:
scZoUnD [109]3 years ago
7 0
<span>When K is > than 1 products are favored. When q is < less than 1 reactants are favored. 1 x 108 = 108 which is > 1 so products are favored.</span>
Amiraneli [1.4K]3 years ago
3 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants. It is represented as K_{eq}

For the general reaction:

A+B\rightarrow C+D

Expression for equilibrium constant is given as:

K_{eq}=\frac{[C][D]}{[A][B]}

Conditions for K_{eq} are:

K_{eq}>1, then products are favored

K_{eq}=1, then forward reaction is equal to backward reaction

K_{eq}, then reactants are favored

As, K_{eq}=1\times 10^8 and is very much greater than 1, so products will be favored.

Hence, the correct answer is Option A.

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4 0
3 years ago
Read 2 more answers
Given the following equation: 2K + Cl2 -&gt; 2KCl How many grams of KCl is produced from 4.00 g of K and excess Cl2?
Thepotemich [5.8K]

Answer:

42.65g

Explanation:

Given parameters:

Mass of K = 4g

Unknown: Mass of KCl

Solution:

  Complete equation of the reaction:

              2K + Cl₂ → 2KCl

To solve this problem, we know that the reactant in short supply is potassium K and this dictates the amount of products that would be formed. The chlorine gas is in excess and we can't use it to determine the amount of product that would form.

Now, we work from the known to the unknown. Since we know the mass of K given in the reaction, we can simply find the molar relationship between the reacting potassium and the product. We simply convert the mass to mole and compare to the product. From there we can find the mass of KCl that would be produced.

Calculating number of moles of K

      Number of moles = \frac{mass}{molar mass}

        Number of moles of K =  \frac{4}{39} = 0.103mol

From the given reaction equation:

   2 moles of K will produce 2 moles of KCl

 Therefore 0.103mol of K will produce 0.103mol of KCl

To find the mass of KCl produced,

   Mass of KCl = number of moles of KCl x molar mass

Molar mass of KCl = 39 + 35.5 = 74.5gmol⁻¹

Mass of KCl = 0.103 x 74.5 = 42.65g

4 0
3 years ago
Read 2 more answers
Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products.
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Explanation:

Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:

Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.

Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.

However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.

Elimination of the hydrogen from the methyl group is easier.

Thus, the major product will A

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3 years ago
How many moles are in 43.9 L of oxygen
Ede4ka [16]

Answer: 2 mol

Explanation:

- According to the ideal gas law, One mole of an ideal gas at STP (standard temperature and normal pressure) occupies 22.4 liters.

- Using cross multiplication,

                               1 mol of (O2)        →       22.4 L

                                       ?                   →        43.9 L

Therefore, the number of moles of oxygen in 43.9 L = (43.9 × 1)/ 22.4 = 1.96 mol≈ 2 mol..


3 0
3 years ago
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