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Debora [2.8K]
3 years ago
5

Sometimes Combination reaction takes place sometimes decomposition and sometime replacement.. Can someone say me the conditions

required for it?
Do not tell the defination of decomposition, replacement and of combination.. During reaction sometimes gas is formed sometimes not..
Can Some one explain it in a well manner.. Do not give Undesirable answer:​
Chemistry
2 answers:
yKpoI14uk [10]3 years ago
6 0

Answer:

<h2>Question:</h2>

Sometimes Combination reaction takes place sometimes decomposition and sometime replacement. Explain it in a well mannered way.

<h2>Answer :</h2>

  • When a more reactive element <em>displaces</em> a less reactive element from its compound then <em>Replacement</em><em> </em><em>reaction</em><em> </em><em>takes </em><em>place</em><em>.</em>
  • The condition for a <em>combination </em><em>reaction </em>to take place is when two reactants form a <em>single </em><em>product.</em>
  • The condition for a Decomposition reaction to take place is when A compound <em>breaks</em> down <em>into two</em> simpler substances.

<em><u>Hope </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em>

-------☆゚.・。゚ᵴɒƙυᴚᴀ_ƨȶäᴎ❀

Rina8888 [55]3 years ago
5 0

Whenever any substance goes under chemical change so any of the reaction will happen either both or multiple compounds will combine to produce combination reaction either one compound will decompose itself into 2 or more compounds or elements and last one is replacement reaction the either reaction is not even going to combination nor decomposition, So when a reaction like that happens it must replacement reaction.

Now the question is what's the condition required for it, so basically a chemical reaction when takes place it depends upon several factor on the basis of which we conclude products. The factors are Temperature,catalyst,reagents, either what is the mechanism of reaction, stability of reactants and stability of products and alot more.

During reaction sometimes gas forms and sometimes not yea and well that also depends on the chemical reactivity and stability of product sometimes product found itself most stable releasing the gas evolving so it's been done itself and sometimes we add catalyst and adjust the reaction to extract that gas and get desirable product manually.

I wrote all i know if sorry if this is not what you're looking for :(

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180m/173 Tl -&gt; 180/173 Tl + ? Express your answer as a nuclear equation ​
Law Incorporation [45]

Answer: The nuclear equation is ^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma.

Explanation:

A nuclear reaction in which a heavy particle splits into another particle along with release of energy is called a nuclear fission reaction.

For example, ^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma

Here, energy is radiated in the form of gamma radiation.

Thus, we can conclude that the nuclear equation is ^{180}_{173}Tl \rightarrow ^{180}_{173}Tl + ^{0}_{0}\gamma.

4 0
2 years ago
If 1.38×1022 atoms of element y have a mass of 1.50 g, what is the identity of y? express your answer as a chemical symbol.
zaharov [31]
1,38×10²² = 0,138×10²³

0,138×10²³ ----- 1,5g
6,02×10²³ ------ X
X = (1.5×6,02×10²³)/0,138×10²³
X = 65,435 g/mol

It's ZINC (Zn)

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3 years ago
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What term represents a compound
alukav5142 [94]
Compound can be described using element symbol and numbers .  it is a mixture which is result of two or more chemical element in such a way that atoms of different elements held together  by chemical compound that are difficult to break . Most often a compound looks and behave like an element 
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What is the answer and why
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In the spring of 1984, concern arose over the presence of ethylene dibromide, or EDB, in grains and cereals. EDB has the molecul
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869.6 × 10¹⁴ molecules of EDB

Explanation:

We have 1.9 lb of flour with a EDB concentration of 31.5 ppb.

We need to transform lb in grams.

1 lb = 453.6 grams

1.9 lb = (1.9 × 453.6) / 1 = 861.8 grams

Now we determine the number of molecules of EDB in the sample by devise the following reasoning:

if we have        31.5 × 10⁻⁹ g of EDB in 1 g of sample

then we have   X  g of EDB in 861.8 g of sample

X = (31.5 × 10⁻⁹ × 861.8) / 1 = 27146.7 × 10⁻⁹ g of EDB

Molecular mass of EDB (C₂H₄Br₂) = 188 g/mole

Taking in account that 1 mole of any substance contains 6.022 × 10²³ (Avogadro’s number) molecules we devise the following reasoning:

if       188 g of EDB contains 6.022 × 10²³ molecules

then 27146.7 × 10⁻⁹ g of EDB contains Y molecules

Y = (27146.7 × 10⁻⁹ × 6.022 × 10²³) / 188 = 869.6 × 10¹⁴ molecules of EDB

Learn more:

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