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OlgaM077 [116]
2 years ago
10

Select the atoms that belong to the same element

Chemistry
2 answers:
harina [27]2 years ago
8 0

Answer:Top Right and Bottom Right.

Explanation:

Proton's define an elements Identity

Ulleksa [173]2 years ago
3 0

<u>Answer:</u> The atoms which belong to the same element are atom 2 and atom 5.

<u>Explanation:</u>

Elements are identified by their atomic numbers.

Atomic number is defined as the number of protons or number of electrons that are present in an element.

Atomic number = Number of protons = Number of electrons

Two atoms having same number of protons will belong to same element.

From the given image, atom 2 and atom 5 have same number of protons which are 11.

Thus, both the atoms belong to same element.

Hence, the correct answer is atom 2 and atom 5.

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Yuliya22 [10]

1.3 x 10^21 atoms Na is 4.63230769231 mol Na

4.63230769231 mol Na * 23g/mol Na = 106.543076923g

8 0
3 years ago
I’ll give brainlyiest (sorry if I spelled it wrong) to first correct answer
user100 [1]

Answer:

Dependent variable

Hope this helps :)

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5INGH

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Explanation:

8 0
3 years ago
How many moles of KCl are in 2 L of 2.5 M KCl solution?
beks73 [17]
2.5LX2 M=5 moles

As Molarity X Volume= Total Number of Moles
3 0
3 years ago
How many grams do 6 × 1020 atoms of helium weigh? Answer in units of g.
Rzqust [24]
1.2204504e-18   i think   hope this helped 
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2 years ago
In part 2 of the experiment, you will be analyzing a sample of household bleach. A 0.0854 g sample of household bleach is comple
marysya [2.9K]

Answer:

The correct answer is option d.

Explanation:

NaClO(aq)+2KI(s)+H_2O(l)\rightarrow NaCl(aq)+I_2(aq)+2KOH(aq)..[1]

I_2(aq)+2Na_2S_2O_3(aq)\rightarrow 2NaI(aq)+Na_2S_4O_6(aq)..[2]

moles of sodium thiosulfate solution = n

Molarity of the sodium thiosulfate solution = 0.150 M

Volume of sodium thiosulfate solution used = 0.890 mL = 0.00089 L

n=Molarity\times Volume (L)

n=0.150 M\times 0.00089 L=0.0001335 mol

According to reaction [2], 2 moles of sodium thiosulfate reacts with 1 mol I_2.

Then , 0.0001335 mol of sodium thiosulfate will reacts with:

\frac{1}{2}\times 0.0001335 mol=0.00006675 mol of I_2

Moles of I_2 = 0.00006675 mol

According to reaction [1], 1 mol of I_2 is obatnied from 1 mol of NaClO.

Then 0.00006675 mol of I_2 will be obtained from:

\frac{1}{1}\times 0.00006675 mol=0.00006675 mol

Mass of 0.00006675 mol of NaClO=

0.00006675 mol × 74.44 g/mol = 0.00496887 g

Mass of sample = 0.0854 g

Percentage of NaClO in sample:

\frac{0.00496887 g}{0.0854 g}\times 100=5.82\%

4 0
3 years ago
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