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4 years ago

11

(7x+5)(2x^3-4x^2+9x-3)

1 answer:

Fudgin [204]4 years ago

7 0

Answer:

$\large\boxed{(7x+5)(2x^3-4x^2+9x-3)=14x^4-18x^3+43x^2+24x-15}$

Step-by-step explanation:

Use FOIL: <em>(a + b)(c + d) = ac + ad + bc + bd</em>

$(7x+5)(2x^3-4x^2+9x-3)\\\\=(7x)(2x^3)+(7x)(-4x^2)+(7x)(9x)+(7x)(-3)\\+(5)(2x^3)+(5)(-4x^2)+(5)(9x)+(5)(-3)\\\\=14x^4-28x^3+63x^2-21x+10x^3-20x^2+45x-15\\\\\text{combine like terms}\\\\=14x^4+(-28x^3+10x^3)+(63x^2-20x^2)+(-21x+45x)-15\\\\=14x^4-18x^3+43x^2+24x-15$

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gayaneshka [121]

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Step-by-step explanation:

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Answer with explanation:

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Read 2 more answers

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Kitty [74]

Answer:

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Step-by-step explanation:

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