1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dvinal [7]
3 years ago
11

10. What mass of glass (Cp = 0.749 J/gºC) is needed to absorb 5.00x104 J of heat, if it starts at 26.0 C and has a final tempera

ture of 275.0°C?​
Chemistry
1 answer:
morpeh [17]3 years ago
8 0

Answer:

m = 0.03  × 10⁴ g

Explanation:

Given data:

Specific heat capacity = 0.749 j/g.°C

Heat absorbed = 5.0 × 10⁴ J

Initial temperature = 26.0 °C

Final temperature = 275.0 °C

Mass = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = T2-T1

ΔT  = 275.0 °C - 26.0 °C

ΔT  = 249  °C

Q = m.c. ΔT

m = Q / c. ΔT

m =  5.0 × 10⁴ J / 0.749 j/g.°C  × 249  °C

m =  5.0 × 10⁴ J / 186.5  j/g

m = 0.03  × 10⁴ g

You might be interested in
The length of a spring when it's at rest is measured to be 0.56 centimeter. How many significant figures are there in this measu
lukranit [14]
Two. The zero before the decimal is insignificant
8 0
3 years ago
Find the pressure of a gas if the volume is 2.00 L, the temperature is 310 Kelvin and
kipiarov [429]

Answer:

25.42 atm

Explanation:

Data Given:

Volume of a gas ( V )= 2.00 L

temperature of a gas ( T ) =  310 K

number of moles (n) = 2​ mol

Pressure of a gas ( P ) = to be find

Solution:

Formula to be used

              PV= nRT

Rearrange the above formula

              P = nRT / V . . . . . . . . . . (1)

Where R is ideal gas constant

R = 0.08205 L atm mol⁻¹ K⁻¹

Put values in equation 1

                 P = nRT / V

                  P = 2 mol x 0.08205 L atm mol⁻¹ K⁻¹ x 310 k / 2 L

                  P = 50.84 L atm / 2 L

                  P = 25.42 atm

P ressure of gas (P) will be = 25.42 atm

7 0
3 years ago
How much heat energy is needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C? The specific heat of cadmium is
Ilia_Sergeevich [38]
Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the change in temperature. It is expressed as: 

<span>Energy = mCΔT
</span><span>Energy = 59.7 (0.231) (100-25)
</span><span>Energy = 1034.30 J</span>
3 0
3 years ago
A chemist has a 3.25-mole sample of potassium (K) to use in an experiment. What is the mass of this sample?
s344n2d4d5 [400]
Hi!
• For this you want to convert moles to grams
• To do this you would simply multiple your moles times the atomic mass of potassium
3.25 x 39.098= 127.0685
• So your answer for this should be about 127.07 depending on how you need to round!
5 0
2 years ago
A rock weighing 26.0 g is placed in in a graduated cylinder displacing the volume from 13.2mL to 25.3 mL. What is the density of
SSSSS [86.1K]
2.11487 grams/cubic centimeter
5 0
3 years ago
Read 2 more answers
Other questions:
  • What is the difference between the low tide and the high tide
    7·1 answer
  • Write the full ground state electron configuration of f+.
    7·1 answer
  • In a resting state, sodium (Na ) is at a higher concentration outside the cell and potassium (K ) is more concentrated inside th
    14·1 answer
  • What is the first element on the periodic table?
    7·2 answers
  • When two substances are mixed and light is produced is it a chemical or physical change?
    8·2 answers
  • Select the number that are signicantbin the number 1500 ?
    12·1 answer
  • 2.1. Three moles of an ideal gas (with temperature-independent CP = (7/2)R, CV = (5/2)R) is contained in a horizontal piston/cyl
    13·1 answer
  • I NEED HELP PLEASE, THANKS SO MUCH! :)
    11·1 answer
  • Condensation point and freezing point of argon in KELVIN.
    13·1 answer
  • Which step you should take before performing a scientific investigation
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!