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11Alexandr11 [23.1K]

3 years ago

11

Identify the location of the dorsal horn in the spinal cord

2 answers:

attashe74 [19]3 years ago

8 0

Answer:

The answer is location B

Explanation:

Cerrena [4.2K]3 years ago

6 0

Answer:Intermediolateral nucleus is located in the intermediate zone between the dorsal and the ventral horns in the spinal cord levels. Extending from C8 to L3, it receives viscerosensory information and contains preganglionic sympathetic neurons, which form the lateral horn.

Explanation:Intermediolateral nucleus is located in the intermediate zone between the dorsal and the ventral horns in the spinal cord levels. Extending from C8 to L3, it receives viscerosensory information and contains preganglionic sympathetic neurons, which form the lateral horn.

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A few substances are arranged in the increasing order of ‘forces of attraction’ between their particles. Which one of the follow

gavmur [86]

Answer:

A.

Explanation:

PO WATER,AIR,WIND

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3 years ago

If a lab experiment is not completed, you should:___________.

stellarik [79]

The answer to this question is a

7 0

3 years ago

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A horse runs 1 km in 15 s. What is the average speed

Reptile [31]

The average speed of the horse for the entire motion is 66.67 m/s.

The given parameters;

<em>distance traveled by the horse, d = 1 km = 1,000 m</em>
<em>time of motion of the horse, t = 15 s</em>

The average speed of the horse is calculated by dividing the total distance traveled by the horse by the time of motion.

The average speed of the horse is calculated as follows;

$average\ speed = \frac{distance}{time} \\\\average\ speed = \frac{1000 \ m}{15 \ s} = 66.67 \ m/s$

Thus, the average speed of the horse for the entire motion is 66.67 m/s.

Learn more here: brainly.com/question/17289046

6 0

3 years ago

You are given a sulfuric acid solution of unknown concentration. You dispense 10.00 mL of the unknown solution into an Erlenmeye

dmitriy555 [2]

Answer:

"0.053457 M" of sulfuric acid.

Explanation:

The given values are:

$V$ = 10 mL solution

$V_{added}$ = 12.20 mL

$V_{total}$ = 22.20 mL

then,

M 0.103 M of NaOH,

$V_{rinsed}$ = experiment will not be affected

$V_{total \ base}$ = 10.38 mL

Now,

⇒ mol of NAOH = MV

= $0.103\times 10.38$

= $1.06914 \ m$

Whether Sulfuric acid, then

⇒ $H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O$

⇒ $mol \ of \ acid =\frac{1}{2}\times \ mol \ of \ base$

⇒ $1.06914 \ m \ mol \ of \ base = \frac{1}{2}\times 1.06914 = 0.53457 \ m \ mol \ of \ acid$

Before any dilution:

$V_{sample} = 10 \ mL$

⇒ $M \ acid = \frac{m \ mol}{V}$

$=\frac{ 0.53457 }{10}$

$=0.053457 \ M$ (Sulfuric acid)

6 0

3 years ago

A compound composed of only carbon and chlorine is 85.5% chlorine by mass. propose a lewis structure for the lightest of the pos

aivan3 [116]

Answer is in picture below.

Use 100 grams of the compound:

ω(Cl) = 85.5% ÷ 100%.

ω(Cl) = 0.855; mass percentage of the chlorine in the compound.

m(Cl) = 0.855 · 100 g.

m(Cl) = 85.5 g; mass of chlorine.

m(C) = 100 g - 85.5 g.

m(C) = 14.5 g; mass of carbon.

n(Cl) = m(Cl) ÷ M(Cl).

n(Cl) = 85.5 g ÷ 35.45 g/mol.

n(Cl) = 2.41 mol; amount of chlorine.

n(C) = 14.5 g ÷ 12 g/mol.

n(C) = 1.21 mol; amount of carbon.

n(Cl) : n(C) = 2.41 mol : 1.21 mol = 2 : 1.

This compound is dichlorocarbene CCl₂.

4 0

3 years ago

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