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tangare [24]
3 years ago
11

How many years old are you if you have lived 1 billion seconds 31 years round this answer to 3 sig figs

Chemistry
1 answer:
stich3 [128]3 years ago
5 0

Answer:

age = 63.2 years

Explanation:

Given data

Number of years = 31

number of seconds = 1 billion

Age = ?

Solution

First we convert seconds to minutes

minutes = 1000000000 / 60

minutes = 16666666.667

Now convert minutes to hours

hours = 16666666.667 / 60

hours = 277777.778

Now convert hours to days

days = 277777.778 / 24

days = 11574.074

Now convert days to months

months = 11574.074 / 30

months = 385.802

Now convert months to years

years = 385.803 / 12

years = 32.15

Now add these years with given years

age = 31 + 32.15

age = 63.2 years

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Which formula can be used to calculate the theoretical yield? (5 points)
Semenov [28]

Answer:

Multiply the number of moles in the product by the molecular weight of the product to determine the theoretical yield.

Explanation:

For example:

If you created 0.5 moles of Aluminium Oxide the molecular weight of Aluminium Oxide is 101.96g/mole, so you would get 50.98g as the theoretical yield.

So multiply,..

101.96x0.5= 50.98

This is the correct way to calculate the theoretical yield

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8 0
3 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolit
natka813 [3]

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

w = 6.2114 grams

Hence, pure aluminum produced in the process is 6.2114 grams.  

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