1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tangare [24]
3 years ago
11

How many years old are you if you have lived 1 billion seconds 31 years round this answer to 3 sig figs

Chemistry
1 answer:
stich3 [128]3 years ago
5 0

Answer:

age = 63.2 years

Explanation:

Given data

Number of years = 31

number of seconds = 1 billion

Age = ?

Solution

First we convert seconds to minutes

minutes = 1000000000 / 60

minutes = 16666666.667

Now convert minutes to hours

hours = 16666666.667 / 60

hours = 277777.778

Now convert hours to days

days = 277777.778 / 24

days = 11574.074

Now convert days to months

months = 11574.074 / 30

months = 385.802

Now convert months to years

years = 385.803 / 12

years = 32.15

Now add these years with given years

age = 31 + 32.15

age = 63.2 years

You might be interested in
What is the name of molecule?
luda_lava [24]

Answer:

functional group - carboxylic

molecule name- propanic acid

7 0
3 years ago
The atomic symbol represents the _____ of the element.
Anarel [89]

Protons

Explanation: the atomic number is the same as the number of protons

4 0
3 years ago
What initial observation led to the Alvarez asteroid-impact theory? a large undersea crater off the coast of the Yucatan Peninsu
Nikitich [7]

Answer: high iridium levels in a 66- million-year-old clay layer in Denmark and Italy

Explanation:

6 0
3 years ago
Read 2 more answers
Balanced nuclear equation forces the alpha decay Po-210
Serjik [45]

Answer:

_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}

Explanation:

Your unbalanced nuclear equation is:

_{84}^{210}\text{Po} \longrightarrow \, _{x}^{y}\text{Z} + \, _{2}^{4}\text{He}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

 84 = x + 2, so x =  84 - 2 =   82

210 = y + 4, so y = 210 - 4 = 206

Element 82 is lead, so the nuclear equation becomes

_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}

8 0
3 years ago
0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
Other questions:
  • Is coffee and water heterogeneous or homogeneous?​
    7·1 answer
  • The mass-to charge ratio of the proton is found to be
    8·1 answer
  • How do you convert 3.9mL to hL
    11·1 answer
  • Who were the scientists who won the nobel prize for the atomic model?
    12·1 answer
  • What is the mass in grams of a sample of 1.20 x 10 22 atoms of mercury?
    8·2 answers
  • Sometimes light behaves like a wave, and sometimes it behaves like a particle. True False
    10·1 answer
  • A solution of H2SO4(aq) with a molal concentration of 5.25 m has a density of 1.266 g/mL. What is the molar concentration of thi
    7·1 answer
  • As the given number of neutrons in the nucleus of a given atom of an element increases, the atomic number of that element
    11·2 answers
  • Calculate the change in temperature of the water in the calorimeter​
    5·1 answer
  • what layers of protection can be used tot detect and respond to abnormal reactions or process conditions
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!