5.7% KCl is 94.3 % water.
Therefore, for 1000 g of water the mass of KCl will be (1000× 5.7)/94.3 = 60.445 grams.
1 mole of KCl is equal to 74.55 g,
therefore, 60.445 g will be 60.445/74.55 = 0.8108 mole of KCl
Hence, 0.8108 moles of KCl should release twice that number of moles 1.6216 moles ions.
Having 1.6216 moles of KCl ions dissolved in 1000g of water, gives us 1.6216 molar if solution.
Using the freezing point depression constant of water.
dT = Kf (molarity)
dT = (1.86 C/ molar) (1.6216 m)
dT = 3.016 C drop in freezing point
Therefore, it should freeze at - 3.016 Celsius
Answer:
Global wind
Explanation:
The jet streams go around the whole earth from west to east
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The temperature : 332.75 K
<h3>Further explanation</h3>
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
volume of gas = 790 cm³ = 0.79 L
mol of gas at STP :

Use ideal gas :

P=726 mmHg=0.955 atm
V= 1000 cm³ = 1 L

There are a total of 6 hydrgen atoms
Dehydrogenation is catalyzed by Cu, Mo and Fe by changing their oxidation states.